MCQ
$XeF_6$ on partial hydrolysis gives
- A$XeF_2$
- ✓$XeOF_4$
- C$XeO_3$
- D$XeOF_2$
✓
Answer
Correct option: B.
$XeOF_4$
b
$Xe{F_6}\xrightarrow[{ - 2HF}]{{ + {H_2}O}}XeO{F_4}$
$Xe{F_6}\xrightarrow[{ - 2HF}]{{ + {H_2}O}}XeO{F_4}$
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