c
\(\underset{\substack{\text { Mol..wt.45g }}}{\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{NH}_2} \xrightarrow{\mathrm{N}_2 \mathrm{NO}_2+\mathrm{HCl}} \xrightarrow{\mathrm{H}_2 \mathrm{O}} \mathrm{CH}_3 \mathrm{CH}_2-\mathrm{OH}+\underset{14 \mathrm{~g}}{\mathrm{~N}_2}\)

given: \(\mathrm{N}_2\) evolved is \(2.24 \mathrm{~L}\) i.e. \(0.1 \mathrm{~mole}\).

1.e. \(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{NH}_2\) (ethyl amine) will be \(4.5 \mathrm{~g}\)

\((=0.1 \mathrm{~mole})\)

Hence the answer \(=45 \times 10^{-1} \mathrm{~g}\)