MCQ
$y = a{e^{mx}} + b{e^{ - mx}}$ નું વિકલ સમીકરણ મેળવો.
- A$\frac{{dy}}{{dx}} - my = 0$
- B$\frac{{dy}}{{dx}} + my = 0$
- C$\frac{{{d^2}y}}{{d{x^2}}} + {m^2}y = 0$
- ✓$\frac{{{d^2}y}}{{d{x^2}}} - {m^2}y = 0$
Differentiating, we get $\frac{{dy}}{{dx}} = ma{e^{mx}} - mb{e^{ - mx}}$.
Differentiating again, we get $\frac{{{d^2}y}}{{d{x^2}}} = {m^2}a{e^{mx}} + {m^2}b{e^{ - mx}}$
$ = {m^2}(a{e^{mx}} + b{e^{ - mx}}) = {m^2}y$ or $\frac{{{d^2}y}}{{d{x^2}}} - {m^2}y = 0$.
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કારણ :વિધાન $- II : x^{1/x}$ એ $0 < x < e $ માટે વધે અને $x > e $ માટે ઘટે છે.