Question
यदि $A=\left[\begin{array}{ll}1 & 2 \\ 3 & 4\end{array}\right]$ हो, तो $A ^{-1}$ का मान होगा-

Answer

(B) $\left[\begin{array}{cc}-2 & 1 \\ \frac{3}{2} & -1 / 2\end{array}\right]$
$-A_{11}=4, A_{12}=-3, A_{21}=-2, A_{22}=1$
$\operatorname{adj} A =\left[\begin{array}{cc}4 & -3 \\ -2 & 1\end{array}\right]^{\prime}=\left[\begin{array}{cc}4 & -2 \\ -3 & 1\end{array}\right]$
$|A|=4-6=-2 \neq 0$
$A ^{-1}=\frac{\operatorname{adj} A }{| A |}=\frac{-1}{2}\left[\begin{array}{cc}4 & -2 \\ -3 & 1\end{array}\right]=\left[\begin{array}{cc}-2 & 1 \\ \frac{3}{2} & -1 / 2\end{array}\right]$
अतः सही विकल्प (B) है।

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