Question
यदि ${\cos ^{ - 1}}\left( {\frac{1}{x}} \right) = \theta $, तब $\tan \theta $=
अब, $\tan \theta = \frac{{\sin \theta }}{{\cos \theta }} = \frac{{\sqrt {1 - {{(1/x)}^2}} }}{{1/x}} = \sqrt {{x^2} - 1} $.
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