Question
यदि $f(x) = \left\{ \begin{array}{l}\;x + 1,\;{\rm{when\,\,}}\,x < 2\\2x - 1,{\rm{when\,\,}}x \ge {\rm{2}}\end{array} \right.$, तो $f'(2)$ बराबर है
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$\left[\frac{x}{\sqrt{x^2-y^2}}+e^{\frac{y}{x}}\right] x \frac{d y}{d x}=x+\left[\frac{x}{\sqrt{x^2-y^2}}+e^{\frac{y}{x}}\right] y$
का हल वक्र $y = y ( x )$ हो जो $(1,0)$ तथा $(2 \alpha, \alpha), \alpha > 0$ से होकर गुजरता हो तब $\alpha$ बराबर होगा