Question
यदि $f(x) = |x - 2|$, तो
$\mathop {\lim }\limits_{x \to 2 - } f(x) = \mathop {\lim }\limits_{h \to 0} \,f(2 - h) = \mathop {\lim }\limits_{h \to 0} \,\,|\,\,2 - h - 2\,\,| = 0$
$\mathop {\lim }\limits_{x \to 2 - } f(x) = \mathop {\lim }\limits_{h \to 0} \,f(2 - h) = \mathop {\lim }\limits_{h \to 0} \,\,|\,\,2 - h - 2\,\,| = 0$
अत: यह $x = 2$ पर सतत् है।
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