MCQ
यदि $\int \frac{x^3 d x}{\sqrt{1+x^2}}=a\left(1+x^2\right)^{\frac{3}{2}}+b \sqrt{1+x^2}+c$, तब
- A$a=\frac{1}{3}, b=1$
- B$a=-\frac{1}{3}, b=1$
- C$a=-\frac{1}{3}, b=-1$
- ✓$a=\frac{1}{3}, b=-1$
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