MCQ
यदि $\sin ^{-1}\left(\frac{1}{2}\right)=x$ तो $x$ का व्यापक मान है$-$
  • A
    $2 n \pi \pm \frac{\pi}{6}$
  • B
    $\frac{\pi}{6}$
  • C
    $n \pi \pm \frac{\pi}{6}$
  • $n \pi+(-1)^n \frac{\pi}{6}$

Answer

Correct option: D.
$n \pi+(-1)^n \frac{\pi}{6}$
$n \pi+(-1)^n \frac{\pi}{6}$
यदि $\sin ^{-1}\left(\frac{1}{2}\right)=x$ तब $\sin x=\frac{1}{2}$
$\sin x=\sin \frac{\pi}{6}$ तब व्यापक मान $x=n \pi+(-1)^n \frac{\pi}{6}$
अतः सही विकल्प $(D)$ है।

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