Question
यदि $\sin \theta + {\rm{cosec}}\theta = {\rm{2}}$, तो ${\sin ^2}\theta + {\rm{cose}}{{\rm{c}}^{\rm{2}}}\theta = $

Answer

c
${\sin ^2}\theta  + {\rm{cose}}{{\rm{c}}^2}\theta$

$  = {(\sin \theta  + {\rm{cosec}}\theta )^2} - 2\sin \theta {\rm{ cosec}}\theta $

$ = {(2)^2} - 2 = 4 - 2 = 2,$

चूँकि $(\sin \theta  + {\rm{cosec}}\theta ) = 2.$

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