Question
यदि $ \sin (x+y)=log(x+y),$ तो $\frac{{dy}}{{dx}} =$
$\frac{{dy}}{{dx}} = - \frac{{\partial f/\partial x}}{{\partial f/\partial y}} $
$= - \frac{{\cos (x + y) - \frac{1}{{x + y}}}}{{\cos (x + y) - \frac{1}{{x + y}}}} = - 1$.
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