Question
यदि $\tan \theta = \frac{{ - 4}}{3},$ तो $\sin \theta = $
$\left( \because {\tan \theta = - \frac{4}{3}} \right)$
${\sin ^2}\theta = \frac{1}{{{\rm{cose}}{{\rm{c}}^2}\theta }} = \frac{{16}}{{25}} \Rightarrow \sin \theta = \pm \frac{4}{5},$
दोनों मान हो सकते हैं, क्योंकि $\tan \theta = - \frac{4}{3}\,\,$
अर्थात् $\theta $ दूसरे व चौथे चतुर्थांश में है।
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