Question
यदि $x = {t^2}$, $y = {t^3}$, तो $\frac{{{d^2}y}}{{d{x^2}}} =$
$\Rightarrow \frac{{{d^2}y}}{{d{x^2}}} = \frac{3}{{4\sqrt x }} = \frac{3}{{4t}}$.
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$I.$ $P\,\left( {\frac{{{A^c}}}{{{B^c}}}} \right) = \frac{3}{4}$
$II.$ घटनायें $A$ तथा $B$ परस्पर अपवर्जी है
$III.$ $P\left( {\frac{A}{B}} \right) + P\left( {\frac{A}{{{B^c}}}} \right) = 1$