MCQ
यदि $x^y=e^{x-y}$ तब $\frac{d y}{d x}$
- ✓$\frac{-1}{(1+\log x)^2}$
- Bnot defined
- C$\frac{1+x}{1+\log x}$
- D$\frac{1-\log x}{1+\log x}$
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