Question
यदि $y = {3^{{x^2}}}$, तब $\frac{{dy}}{{dx}} = $
$\because \frac{d}{{dx}}({a^x}) = {a^x}{\log _e}a$
$\therefore \frac{{dy}}{{dx}} = {3^{{x^2}}}{\log _e}3\frac{d}{{dx}}({x^2})$
==> $\frac{{dy}}{{dx}} = {3^{{x^2}}}.2x.{\log _e}3$ .
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.