Question
यदि $y = \sqrt {\frac{{1 + \tan x}}{{1 - \tan x}}} $, तो $\frac{{dy}}{{dx}} = $
$\frac{{dy}}{{dx}} = \frac{1}{{2\sqrt {\tan \left( {\frac{\pi }{4} + x} \right)} }}{\sec ^2}\left( {\frac{\pi }{4} + x} \right)$
$ = \frac{1}{2}\sqrt {\left[ {\frac{{1 - \tan x}}{{1 + \tan x}}} \right]} {\sec ^2}\left( {\frac{\pi }{4} + x} \right)$.
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