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A given nitrogen-containing aromatic compound $'A'$ reacts with $Sn/HCl,$ followed by $HNO_2$ to give an unstable compound $'B'$. $ 'B',$ on treatment with phenol, forms a beautiful coloured compound $'C'$ with the molecular formula $C_{12}H_{10}N_2O.$ The structure of compound $'A'$ is
A compound with molecular mass $180$ is acylated with $CH_3COCl$ to get a compound with molecular mass $390.$ The number of amino groups present per molecule of the former compound is :
$RN{H_2}$ reacts with ${C_6}{H_5}S{O_2}Cl$ in aqueous $KOH$ to give a clear solution. On acidification a precipitate is obtained which is due to the formation of