${E_{cell}}\, = \,\,E_{cell}^ \circ \, + \,\,\frac{{0.059}}{2}\log \,\,\frac{{[F{e^{ + 2}}]}}{{[Z{n^{ + 2}}]}}$
$0.2905\,\, = \,\,E_{cell}^ \circ \, + \,\,\frac{{0.059}}{2}\,\log \,\frac{{0.01}}{{0.1}}$
$\therefore \,E_{cell}^ \circ \, = \,\,0.2905\,\, + \,\,0.0295\,\, = \,\,0.32\,\,volt$
$Now,\,\,\,E_{cell}^ \circ \, = \,\,\frac{{0.059}}{2}\,\,\log \,\,{K_c}$
$0.32\,\, = \,\,\frac{{0.059}}{2}\,\log \,\,{K_c}$
$KC\,\, = \,\,{10^{0.32/0.0295}}$
$Pt|{H_2}_{\left( {1{\mkern 1mu} atm} \right)}|0.1{\mkern 1mu} M{\mkern 1mu} HCl||{\mkern 1mu} {\mkern 1mu} 0.1{\mkern 1mu} M\,C{H_3}COOH|{H_2}_{\left( {1{\mkern 1mu} atm} \right)}|Pt$
$Pt | H_2\,(g) | H^{+}_{(aq)} (10^{-8}\, M) | | H^{+}_{(aq)} (0.001\,M) | H_2\,(g) | Pt$