Questions

3 Marks Question

Take a timed test

4 questions · self-marked practice — reveal the answer and mark yourself.

Question 13 Marks
Construct an obtuse angled triangle which has a base of $5.5\ cm$ and base angles of $30^\circ $ and $120^\circ .$
Answer


Steps of construction:
Step I: Draw a line segment $SC$ of length $5.5\ cm.$
Step II: Draw an angle of $120^\circ $ on point $S$ and produce it to ray $Y.$
Step III: Draw an angle of $30^\circ $ on point $C$ and produce it to ray $X.$
Step IV: Extend $BY$ and $CX$ to intersect at point $A.$
Hence,
$\triangle\text{ABC}$ is the required triangle with $BC = 5.5,$
$\angle\text{ABC}=120^\circ$ and $\angle\text{ACB}=30^\circ$
View full question & answer
Question 23 Marks
Draw a triangle whose sides are of lengths $4\ cm, 5\ cm$ and $7\ cm.$
Answer


Let us assume that given sides are $BC = 7\ cm, AS = 4\ cm$ and $AC = 5\ cm$
Steps of construction:
Step I: Draw a line $BC = 7\ cm.$​​​​​​​
Step II: With centre $B$ and radius $4\ cm$ draw an arc.
Step III: With centre $C$ and radius $5\ cm,$ draw an arc which cuts the previous arc at $A.$​​​​​​​
Step IV: Join $AB$ and $AC.$
Hence, $\triangle\text{ABC}$ is the required triangle in which
$AB = 4\ cm$
$BC = 7\ cm$
$AC = 5\ cm.$
View full question & answer
Question 33 Marks
Draw two parallel lines at a distance of $2.2\ cm$ apart
Answer


Steps of construction:
Step I: Draw a line $l$ and mark a point $C$ outside it.
Step II: Take a point $B$ on line $l$ and join $BC.$
Step III: Draw line parallel to line $l$ passing through $C$.
Step IV: Mark a point $D$ on line $m,$ at a distance of $2.2\ cm$ from $C.$ Step $V$ Through $D$ draw $AD || BC.$
Line $l$ is parallel to line $m$
Also,
$AD || BC,$
$AB = DC = 2.2\ cm$
View full question & answer
Question 43 Marks
Construct a right-angled isosceles triangle with one side (other than hypotenuse) of length $4.5\ cm.$
Answer

Steps of construction:
Step I Draw a line $AB = 4.5\ cm.$
Step II Construct a right angle $(90^\circ )$ at point $B,$ i.e. $\angle ABY = 90^\circ .$
Step III From point $B,$ cut an arc $4.5cm$ on $BY$ at $C.$​​​​​​​
Step IV Join $C$ to $A.$ Hence, $\triangle ABC$ is the required triangle having $AB - AC = 4.5\ cm.$
View full question & answer