MCQ 1011 MarkIf $\frac{5+9+13+\cdots \text { to } n \text { terms }}{7+9+11+\cdots \text { to }(n+1) \text { terms }}=\frac{17}{16}$, then $n=$A8✓7C10D11AnswerCorrect option: B. 7B View full question & answer→
MCQ 1021 MarkIf the first term of an A.P. is $a$ and $n^{\text {th }}$ term is $b$, then its common difference isA$\frac{b-a}{n+1}$✓$\frac{b-a}{n-1}$C$\frac{b-a}{n}$D$\frac{b+a}{n-1}$AnswerCorrect option: B. $\frac{b-a}{n-1}$B View full question & answer→
MCQ 1031 MarkThe 9 th term of an A.P. is 449 and 449 th term is 9 . The term which is equal to zero isA$501^{\text {th }}$B$502^{\text {th }}$✓$458^{ th }$Dnone of theseAnswerCorrect option: C. $458^{ th }$C View full question & answer→
MCQ 1041 MarkSum of $n$ terms of the series $\sqrt{2}+\sqrt{8}+\sqrt{18}+\sqrt{32}+\cdots$ isA$\frac{n(n+1)}{2}$B$2 n(n+1)$✓$\frac{n(n+1)}{\sqrt{2}}$D1AnswerCorrect option: C. $\frac{n(n+1)}{\sqrt{2}}$C View full question & answer→
MCQ 1051 MarkThe number of terms of the A.P. $3,7,11,15, \ldots$ to be taken so that the sum is 406 isA5B10C12✓14AnswerCorrect option: D. 14D View full question & answer→
MCQ 1061 MarkIf the first term of an A.P. is 2 and common difference is 4 , then the sum of its 40 terms is✓3200B1600C200D2800AnswerCorrect option: A. 3200A View full question & answer→
MCQ 1071 MarkIf four numbers in A.P. are such that their sum is 50 and the greatest number is 4 times the least then the numbers are✓$5,10,15,20$B$4,10,16,22$C$3,7,11,15$Dnone of theseAnswerCorrect option: A. $5,10,15,20$A View full question & answer→
MCQ 1081 MarkThe first and last terms of an A.P. are 1 and 11. If the sum of its terms is 36, then the number of terms will beA5✓6C7D8AnswerCorrect option: B. 6B View full question & answer→
MCQ 1091 Mark$\left(3-\frac{1}{n}\right)+\left(3-\frac{2}{n}\right)+\left(3-\frac{3}{n}\right)+\ldots$ upto $n$ terms isA$\frac{1}{2}(3 n-1)$B$\frac{1}{2}(3 n+1)$✓$\frac{1}{2}(5 n-1)$D$\frac{1}{2}(5 n+1)$AnswerCorrect option: C. $\frac{1}{2}(5 n-1)$C View full question & answer→
MCQ 1101 MarkIf the sum of three consecutive terms of an increasing A.P. is 51 and the product of the first and third of these terms is 273 , then the third term isA13B9✓21D17AnswerCorrect option: C. 21CView full question & answer→
MCQ 1111 MarkIf $18, a, b,-3$ are in A.P., the $a+b=$A19B7C11✓15AnswerCorrect option: D. 15D View full question & answer→
MCQ 1121 MarkThe common difference of an A.P., the sum of whose $n$ terms is $S_n$, is✓$S_n-2 S_{n-1}+S_{n-2}$B$S_n-2 S_{n-1}-S_{n-2}$C$S_n-S_{n-2}$D$S_n-S_{n-1}$AnswerCorrect option: A. $S_n-2 S_{n-1}+S_{n-2}$A View full question & answer→
MCQ 1131 MarkThe $n^{\text {th }}$ term of an A.P., the sum of whose $n$ terms is $S_n$, isA$S_n+S_{n-1}$✓$S_n-S_{n-1}$C$S_n+S_{n+1}$D$S_n-S_{n+1}$AnswerCorrect option: B. $S_n-S_{n-1}$B View full question & answer→
MCQ 1141 MarkIf $\frac{1}{x+2}, \frac{1}{x+3}, \frac{1}{x+5}$ are in A.P. Then, $x=$A5B3✓1D2AnswerCorrect option: C. 1C View full question & answer→