17 questions · timed · auto-graded
$\text{Al}_2\text{O}_3+\text{HCl}\xrightarrow{ \ \ \ \ \ \ \ \ \ \ \ \ }$
$\text{K}_2\text{O}+\text{H}_2\text{O}\xrightarrow{ \ \ \ \ \ \ \ \ \ \ \ \ }$
$\text{Fe}+\text{H}_2\text{O}\xrightarrow{ \ \ \ \ \ \ \ \ \ \ \ \ }$
$\text{Al}_2\text{O}_3+6\text{HCl}\rightarrow2\text{AlCl}_3+3\text{H}_2\text{O}$
$\text{K}_2\text{O}+\text{H}_2\text{O}\rightarrow2\text{KOH}$
$3\text{Fe}+4\text{H}_2\text{O}\rightarrow\text{Fe}_3\text{O}_4+4\text{H}_2$
$\text{X}+\text{CuSO}_4\rightarrow$Displacement reaction
$\text{X}+\text{ZnSO}_4\rightarrow$Displacement reaction
$\text{X}+\text{AgNO}_3\rightarrow$Displacement reaction
$\text{X}>\text{Zn}>\text{Cu}>\text{Ag}$
Zn + H2SO4 → ZnSO4 + H2
Mg + 2HCl → MgCl2 + H2
2Al + 3H2SO4 → Al2(SO4)3 + 3H2
Fe + 2HCl → FeCl2 + H2
$\text{NH}_4\text{Cl}\text{(s)}+\text{H}_2\text{O}\text{(l)}\xrightarrow{\text{hydrolysis}}\text{NH}_4\text{OH}\text{(aq)}+\text{HCl(aq)}$


$2\text{NaHCO}_3\rightarrow\text{Na}_2\text{CO}_3+\text{H}_2\text{O + CO}_2\uparrow$
Presence of CO2 can be detected with the help of lime water which turns milky after reacting with carbon dioxide gas Washing soda is sodium carbonate deca-hydrate (Na2CO3.10H2O) which means there are 10 water molecules present with crystal hence named as water of crystallization On heating washing soda, it becomes anhydrous and presence of water of crystallization can be detected with the help of anhydrous CuSO4 which shows colour change from white to blue with moisture. Na2CO3.10H2O → Na2CO3 + 10H2OSodium hydrogen carbonate formed is only slightly soluble in water, so it precipitates out as a solid.
The anhydrous sodium carbonate obtained here is called soda ash.
NaCl, Ca(OH)2, NaHCO3, NH3, Na2CO, H2O, Cl2, CO2, CaSO4.2H2O, 2CaSO4.H2O, CaOCl2



$\text{NaOH}+\text{Zn}\rightarrow\text{Na}_2\text{ZnO}_2+\text{H}_2$
Hence, compound A is sodium zincate Na2ZnO2 Reaction:$\text{NaOH}+\text{HCl}\rightarrow\text{NaCl}+\text{H}_2\text{O}$
Hence, compound B is sodium chloride NaCl Reaction:$\text{NaOH}+\text{CH}_3\text{COOH}\rightarrow\text{CH}_3\text{COONa}+\text{H}_2\text{O}$
Hence, compound C is sodium acetate. Thus, X is NaOH. A is sodium zincate (Na2ZnO2) B is common salt (NaCl) C is sodium acetate (CH3COONa)$\text{CaCO}_3+\text{dil. 2HCl}\rightarrow\text{CaCl}_2+\text{H}_2\text{O + CO}_2\uparrow$
When carbon dioxide gas is passed through lime water or calcium hydroxide (Ca(OH)2), it gives the calcium carbonate back. So Y is calcium hydroxide.$\text{Ca(OH)}_2+\text{CO}_2\rightarrow\text{CaCO}_3\downarrow+\text{H}_2\text{O}$
Brine is saturated solution of sodium chloride (NaCl). Electrolysis of brine forms hydrogen gas at cathode and chlorine gas at anode.$2\text{NaCl}+2\text{H}_2\text{O}\xrightarrow{\text{Electrolysis}}2\text{NaOH + Cl}_2\text{(g) + H}_2\text{(g)}$
So G is chlorine gas which is passed through dry calcium hydroxide (Ca (OH)2), produces bleaching powder, CaOCl2 (Z). Ca(OH)2 + Cl2 → CaOCl2 + H2O Hence, X = Calcium carbonate; Y = Lime water; G = Chlorine gas and Z = Calcium oxychloride or bleaching powder| Sabstance | pH | Sabstance | pH |
| Apples | 3.0 | Salt | 7.0 |
| Baking soda | 8.5 | Sugar | 7.0 |
| Black coffee | 5.0 | Toothpaste | 9.0 |
| Houshold ammonia | 12.0 | Vinegar | 3.0 |
| Lemon juice | 2.5 | Washing soda | 11.5 |
| Milk | 6.0 |