Question 12 Marks
Calculate the equivalent resistance of the following electric circuit:
Answer
View full question & answer→$\mathrm{R}_{\mathrm{S}}=\mathrm{R}_{3}+\mathrm{R}_{4}=10+10=20 \Omega$
$\frac{1}{R_{P}}=\frac{1}{R_{2}}+\frac{1}{R_{S}}$
$=\frac{1}{20}+\frac{1}{20}=\frac{1}{10} \Omega$
$\mathrm{R}_{\mathrm{p}}=10 \Omega$
Total equivalent resistance $=\mathrm{R}=\mathrm{R}_{1}+\mathrm{R}_{\mathrm{P}}+\mathrm{R}_{5}$
$=\mathrm{R}=20+10+10=40 \Omega$
$\frac{1}{R_{P}}=\frac{1}{R_{2}}+\frac{1}{R_{S}}$
$=\frac{1}{20}+\frac{1}{20}=\frac{1}{10} \Omega$
$\mathrm{R}_{\mathrm{p}}=10 \Omega$
Total equivalent resistance $=\mathrm{R}=\mathrm{R}_{1}+\mathrm{R}_{\mathrm{P}}+\mathrm{R}_{5}$
$=\mathrm{R}=20+10+10=40 \Omega$
