Question 11 Mark
Assertion (A): The refractive index of diamond is $\sqrt{6}$ and refractive index of liquid is $\sqrt{3}$. If the light travels from the diamond to the liquid, it will initially be reflected when the angle of incidence is $30^{\circ}$.
Reason (R): $\mu=\frac{1}{\sin C}$, where $\mu$ is the refractive index of diamond with respect to liquid.
Reason (R): $\mu=\frac{1}{\sin C}$, where $\mu$ is the refractive index of diamond with respect to liquid.
Answer
View full question & answer→(A) Both A and R are true and R is the correct explanation of A .
Explanation:
Refractive index of diamond w.r.t. liquid
${ }^{l} \mu_{b}=\frac{1}{\sin C}=\frac{\mu_{d}}{\mu_{1}}$
$\frac{\sqrt{6}}{\sqrt{3}}=\frac{1}{\sin C}$
$\sin \mathrm{C}=\frac{1}{\sqrt{2}}=\sin 45^{\circ}$
$\mathrm{C}=45^{\circ}$
Explanation:
Refractive index of diamond w.r.t. liquid
${ }^{l} \mu_{b}=\frac{1}{\sin C}=\frac{\mu_{d}}{\mu_{1}}$
$\frac{\sqrt{6}}{\sqrt{3}}=\frac{1}{\sin C}$
$\sin \mathrm{C}=\frac{1}{\sqrt{2}}=\sin 45^{\circ}$
$\mathrm{C}=45^{\circ}$