MCQ 2511 Mark
A magnet when placed perpendicular to a uniform field of strength $10^{-4} \mathrm{~Wb} / \mathrm{m}^2$ experiences a maximum couple of moment $4 \times 10^{-5} \mathrm{~N} / \mathrm{m}$. What is its magnetic momen
- ✓$0.4\ \mathrm{A} \times \mathrm{m}^2$
- B$0.2\ \mathrm{A} \times \mathrm{m}^2$
- C$0.6\ \mathrm{A} \times \mathrm{m}^2$
- D$0.04\ \mathrm{A} \times \mathrm{m}^2$
Answer
View full question & answer→Correct option: A.
$0.4\ \mathrm{A} \times \mathrm{m}^2$
(a) $0.4\ \mathrm{A} \times \mathrm{m}^2$





