Question 511 Mark
What is $100\%$ of $500?$
Answer
View full question & answer→We have, $100\%$ of $500$
$=\frac{100}{100}\times500=500$
$=\frac{100}{100}\times500=500$
Questions · Page 2 of 2
1 Marks Question
Question 521 Mark
Answer
View full question & answer→We know, Percentage $=$ Fraction $×\ 100$
$\text{Fraction}=\frac{\text{Percentage}}{100}$
$\text{Decimal}=\frac{\text{Percentage}}{100}$
Now, according to these formulae, we have.
$\text{Fraction}=\frac{\text{Percentage}}{100}$
$\text{Decimal}=\frac{\text{Percentage}}{100}$
Now, according to these formulae, we have.
| Percentage | Fraction | Decimal |
| $0\%$ | $0$ | $0$ |
| $10\%$ | $\frac{1}{10}$ | $0.1$ |
| $20\%$ | $\frac{1}{5}$ | $0.2$ |
| $30\%$ | $\frac{3}{10}$ | $0.3$ |
| $40\%$ | $\frac{2}{5}$ | $0.4$ |
| $50\%$ | $\frac{1}{2}$ | $0.5$ |
| $60\%$ | $\frac{3}{5}$ | $0.6$ |
| $70\%$ | $\frac{7}{10}$ | $0.7$ |
| $80\%$ | $\frac{4}{5}$ | $0.8$ |
| $90\%$ | $\frac{9}{10}$ | $0.9$ |
| $100\%$ | $1$ | $1$ |
Question 531 Mark
Sonal bought a bed sheet for $Rs. 400$ and sold it for $Rs. 440.$ Her ____$ \%$ is ___$\%$.
Answer
View full question & answer→Given, $CP$ of a bed sheet $= Rs. 400$ and $SP$ of a ned sheet $= Rs. 440$
Since, $CP > SP$
$\therefore$ Profit $= SP - CP = 440 - 400 = Rs. 40$
Now, $\text{Profit}\%=\frac{\text{Profit}}{\text{CP}}\times100\%=\frac{40}{400}\times100\%=10\%$
Hence, Sonal's Profit$\%$ is $10\%$
Since, $CP > SP$
$\therefore$ Profit $= SP - CP = 440 - 400 = Rs. 40$
Now, $\text{Profit}\%=\frac{\text{Profit}}{\text{CP}}\times100\%=\frac{40}{400}\times100\%=10\%$
Hence, Sonal's Profit$\%$ is $10\%$
Question 541 Mark
$30\%$ of $Rs. 360 =$ ________.
Answer
View full question & answer→We have, $30\%$ of $\text{Rs. }360=\frac{30}{100}\times360 = \text{Rs. }108$
Question 551 Mark
$0.018$ is equivalent to $8\%.$
Answer
View full question & answer→Given, decimal $= 0.018.$
In percentage, $0.018 \times 100= 1.8\%$
Hence, $0.018$ is equivalent to $1.8\%.$
In percentage, $0.018 \times 100= 1.8\%$
Hence, $0.018$ is equivalent to $1.8\%.$
Question 561 Mark
Express $\frac{1}{6}$ as a per cent.
Answer
View full question & answer→We have, $\frac{1}{6}$ In percentage,
$\frac{1}{6}\times100\%=\frac{50}{3}=16.6\% [$to convert in per cent, mulitply by $100]$
$\frac{1}{6}\times100\%=\frac{50}{3}=16.6\% [$to convert in per cent, mulitply by $100]$
Question 571 Mark
Write $0.089$ as a per cent.
Answer
View full question & answer→We have, $0.089$
In percentage, $0.089 \times 100\% = 8.9\% [$to convert in per cent, multiply by $100]$
In percentage, $0.089 \times 100\% = 8.9\% [$to convert in per cent, multiply by $100]$
Question 581 Mark
$Rs. 6400$ were lent to Feroz and Rashmi at $15\%$ per annum for $3\frac{1}{2}$ and $5$ year, respectively. The difference in the interests paid by them is $Rs. 150.$
Answer
View full question & answer→Given, Feroz borrowed $Rs. 6400$ for $3 \frac{1}{2}$ year at $15 \%$
Here, $P_1=$ Rs. $6400, T_1=3 \frac{1}{2}=\frac{7}{2}$ year and $R_1=15 \%$
$\therefore \mathrm{I}=\frac{\mathrm{P}_1 \times \mathrm{R}_1 \times \mathrm{T}_1}{100}$
$=\frac{6400 \times 15 \times 7}{100 \times 2}=\text { Rs. } 3360$
Rasmi borrowed $Rs. 6400$ for $5$ year at $15 \%$
Here, $P_2=$ Rs. $6400, R_2=15 \%$ and $T_2=5$ year
$\therefore \mathrm{I}_2=\frac{\mathrm{P}_2 \times \mathrm{R}_2 \times \mathrm{T}_2}{100}$
$=\frac{6400 \times 15 \times 5}{100}=\text { Rs. } 4800$
$\therefore$ Difference between interests $=4800-3360= Rs. 1440$
Hence, the difference in interest, paid by them is $Rs. 1440 .$
Here, $P_1=$ Rs. $6400, T_1=3 \frac{1}{2}=\frac{7}{2}$ year and $R_1=15 \%$
$\therefore \mathrm{I}=\frac{\mathrm{P}_1 \times \mathrm{R}_1 \times \mathrm{T}_1}{100}$
$=\frac{6400 \times 15 \times 7}{100 \times 2}=\text { Rs. } 3360$
Rasmi borrowed $Rs. 6400$ for $5$ year at $15 \%$
Here, $P_2=$ Rs. $6400, R_2=15 \%$ and $T_2=5$ year
$\therefore \mathrm{I}_2=\frac{\mathrm{P}_2 \times \mathrm{R}_2 \times \mathrm{T}_2}{100}$
$=\frac{6400 \times 15 \times 5}{100}=\text { Rs. } 4800$
$\therefore$ Difference between interests $=4800-3360= Rs. 1440$
Hence, the difference in interest, paid by them is $Rs. 1440 .$
Question 591 Mark
$75\%\frac{4}{3}.$
Answer
View full question & answer→We have. $75\%$ In fraction,
$\frac{75}{100}=\frac{3}{4}$
$\therefore75\%=\frac{3}{4}$
$\frac{75}{100}=\frac{3}{4}$
$\therefore75\%=\frac{3}{4}$
Question 601 Mark
A fruit seller purchased $20\ kg$ of apples at $Rs. 50$ per kg. Out of these, $5\%$ of the apples were found to be rotten. If he sells the remaining apples at $Rs. 60$ per kg, then his _____ is _____%.
Answer
View full question & answer→We have, price for par $kg$ apples $= Rs. 50$
Total purchased appies $= 20\ kg$
Since, $5\%$ were rotten, so good apples $= 20\ kg - 5\%$ of $20\ kg ($rotten$)$
$=20-\frac{5}{100}\times20=20-1=19\text{kg}$
Also, he sells $19\ kg$ apples at $Rs. 60$ per kg.
$\therefore$ Total seilling price $= 19 \times 60 = Rs. 1140$
$\therefore$ Cost price was $20\ kg$ appies $= 20 \times 50 = Rs. 1000$
$\therefore$ Profit $= SP - CP = 1140 - 1000 = Rs. 140$
Now, $\text{profit}\%=\frac{\text{Profit}}{\text{CP}}\times100\%=\frac{140}{10}=14\%$
So, his profit is $14\%$
Total purchased appies $= 20\ kg$
Since, $5\%$ were rotten, so good apples $= 20\ kg - 5\%$ of $20\ kg ($rotten$)$
$=20-\frac{5}{100}\times20=20-1=19\text{kg}$
Also, he sells $19\ kg$ apples at $Rs. 60$ per kg.
$\therefore$ Total seilling price $= 19 \times 60 = Rs. 1140$
$\therefore$ Cost price was $20\ kg$ appies $= 20 \times 50 = Rs. 1000$
$\therefore$ Profit $= SP - CP = 1140 - 1000 = Rs. 140$
Now, $\text{profit}\%=\frac{\text{Profit}}{\text{CP}}\times100\%=\frac{140}{10}=14\%$
So, his profit is $14\%$
Question 611 Mark
$250\ cm$ is $4\%$ of $1\ km.$
Answer
View full question & answer→$\therefore250\text{cm}=\frac{250}{100}=2.5$
Now, $4\%$ of $1\ km=\frac{4}{400}\times1000\text{m}=40\text{m}$
Hence, $250\text{cm}\neq4\%\text{ of }1\text{km.}$
Now, $4\%$ of $1\ km=\frac{4}{400}\times1000\text{m}=40\text{m}$
Hence, $250\text{cm}\neq4\%\text{ of }1\text{km.}$
Question 621 Mark
$\frac{8}{5} =$____$\%$
Answer
View full question & answer→We have, $\frac{8}{5}$
In percentage, $\frac{8}{5} \times 100\% = 250\%$
In percentage, $\frac{8}{5} \times 100\% = 250\%$
Question 631 Mark
To convert a decimal into a per cent, we shift the decimal point two places to the _____.
Answer
View full question & answer→ To convert a decimal into a percent, we shift the decimal point two places to the right. Solution:
To convert a decimal into a percent, we shift the decimal point into places to the right.
Question 641 Mark
To convert a fraction into a percent, we ______ it by $100.$
Answer
View full question & answer→To convert a fraction into a percent, we multiply it by $100.$
Question 651 Mark
$12\%$ of $120$ is $100.$
Answer
View full question & answer→Since, $12\%\text{ of }120=\frac{12}{100}\times120=\frac{1440}{100}=144$
Therefore, $12\%$ of $120$ is $14.4$
Therefore, $12\%$ of $120$ is $14.4$
Question 661 Mark
____ is $50\%$ more than $60.$
Answer
View full question & answer→Let number be $x.$
It is given that $x$ is $50\%$ more than $60.$
Therefore, $x = 60 + 50\%$ of $60=60+\frac{50}{100}\times60=60+30=90$
It is given that $x$ is $50\%$ more than $60.$
Therefore, $x = 60 + 50\%$ of $60=60+\frac{50}{100}\times60=60+30=90$
Question 671 Mark
Interest on $Rs. 12500$ at $18\%$ per annum for a period of $2$ year and $4$ months is ______.
Answer
View full question & answer→Given, $P = Rs. 12500$ and $R = 18\%$
$T = 2$ year $4$ months $=\Big(2+\frac{4}{12}\Big)\text{year}=\Big(2+\frac{1}{3}\Big)\text{year}=\frac{7}{3}\text{year}$
We know that, $\text{I}=\frac{\text{P}\times\text{R}\times\text{T}}{100}=\frac{125000\times18\times7}{3\times100}\text{ Rs. }5250$
$T = 2$ year $4$ months $=\Big(2+\frac{4}{12}\Big)\text{year}=\Big(2+\frac{1}{3}\Big)\text{year}=\frac{7}{3}\text{year}$
We know that, $\text{I}=\frac{\text{P}\times\text{R}\times\text{T}}{100}=\frac{125000\times18\times7}{3\times100}\text{ Rs. }5250$
Question 681 Mark
Nasim bought a pen for $Rs. 60$ and sold it for $Rs. 54.$ His _____________ $\%$ is
Answer
View full question & answer→Given, $CP$ of a pen $= Rs. 60$
and $SP$ of pen $= Rs. 54$
Since, $CP > SP$
$\therefore$ Loss $= CP - SP = 60 - 54 = Rs. 6$
Now, $\text{loss}\%=\frac{\text{Loss}}{\text{CP}}\times100\%=\frac{6}{60}\times100\%=10\%$
Hence, Nasim's loss$\%$ is $10\%$
and $SP$ of pen $= Rs. 54$
Since, $CP > SP$
$\therefore$ Loss $= CP - SP = 60 - 54 = Rs. 6$
Now, $\text{loss}\%=\frac{\text{Loss}}{\text{CP}}\times100\%=\frac{6}{60}\times100\%=10\%$
Hence, Nasim's loss$\%$ is $10\%$
Question 691 Mark
Devangi buys a chair for $Rs. 700$ and sells it for $Rs. 750.$ She earns a profit of ______$\%$ in the transaction.
Answer
View full question & answer→Given, $CP$ of chair $= Rs. 700$
$SP$ of chair $= Rs. 750$
We know that, profit $= SP - CP = 750 - 700 = Rs. 50$
Also, profit$\%=\frac{\text{Profit}}{\text{CP}}\times100\%=\frac{50}{700}\times100\%=7\frac{1}{7}\%$
Hence, profit earned by Devangi is $7\frac{1}{7}\%$
$SP$ of chair $= Rs. 750$
We know that, profit $= SP - CP = 750 - 700 = Rs. 50$
Also, profit$\%=\frac{\text{Profit}}{\text{CP}}\times100\%=\frac{50}{700}\times100\%=7\frac{1}{7}\%$
Hence, profit earned by Devangi is $7\frac{1}{7}\%$
Question 701 Mark
Express $\frac{1}{100}$ as a per cent.
Answer
View full question & answer→We have, $\frac{1}{100}$ In percentage, $\frac{1}{100}\times100\%=1\%.$
Question 711 Mark
Amount received after depositing $Rs. 800$ a period of $3$ year at the rate of $12\%$ per annum is $Rs. 896.$
Answer
View full question & answer→Given, $P = Rs. 800, T = 3$ year and $R = 12\%$
$\therefore\text{I}=\frac{\text{P}\times\text{R}\times\text{T}}{100}=\frac{800\times12\times3}{100}=\text{Rs.}1088$
Also, amount, $(A) = P + I = 800 + 288 = Rs.1088$
Hence, then amount received is $Rs. 1088.$
$\therefore\text{I}=\frac{\text{P}\times\text{R}\times\text{T}}{100}=\frac{800\times12\times3}{100}=\text{Rs.}1088$
Also, amount, $(A) = P + I = 800 + 288 = Rs.1088$
Hence, then amount received is $Rs. 1088.$