- A16, 56
- B16, 16
- C56, 16
- D56, 56
- 56, 16
Explanation:
Molecular weight of X2Y3 = 32.0g/0.2mol
X2Y3 = 32.0g/0.2mol = 160g/mol
Molecular weight of X3Y4 = 92.8g/0.4mol
X3Y4 = 92.8g/0.4mol = 232g/mol
Now suppose the atomic weight of X = a and atomic weight of Y = b
Then, 2a + 3b = 160 ......(i)
And, 3a + 4b = 232 ......(ii)
For equ (i)
$\text{A}=\frac{(160-3\text{b})}{2}$
Put value of (i) in (ii)
$3\frac{(160-3\text{b})}{2}+4\text{b}=232$
After solving,
a = 56 and b = 16