Question types

Triangles question types

199 questions across 4 question groups — pick any mix to generate a Maths paper with step-by-step answer keys.

199
Questions
4
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5
Question types
Sample Questions

Triangles questions

One sample from each question group in this chapter. Select any group above to see the full set with answer keys.

In an isosceles $\triangle\text{ABC},$ if $AC = BC$ and $AB^2= 2AC^2$ then $\angle\text{C}=?$
  • A
    $30^\circ $
     
  • B
    $45^\circ$
     
  • C
    $60^\circ$
     
  • $90^\circ$

Answer: D.

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In an equilateral triangle $ABC,$ if $\text{AD}\perp\text{BC}$ then which of the following is true?
  • A
    $ 2 A B^2 =3 A D^2 $
     
  • B
    $ 4 A B^2 =3 A D^2$
     
  • $ 3 A B^2 =4 A D^2 $
     
  • D
    $ 3 A B^2 =2 A D^2 $

Answer: C.

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In $\triangle\text{ABC},\text{DE }||\text{ BC}$ such that $\frac{\text{AD}}{\text{DB}}=\frac{3}{5}.$ $AC = 5.6cm$ then $AE =?$
  • A
    $4.2cm$
  • B
    $3.1cm$
  • C
    $2.8cm$
  • $2.1cm$

Answer: D.

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In a $\triangle\text{ABC},$ it is given that $AD$ is the internal bisector of $\angle\text{A}.$ If $AB = 10cm, AC = 14cm$ and $BC = 6cm,$ then $CD = ?$
  • A
    $4.8cm$
  • $3.5cm$
  • C
    $7cm$
  • D
    $10.5cm$

Answer: B.

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In a $\triangle\text{ABC},$ if $DE$ is drawn parallel to $BC,$ cutting $AB$ and $AC$ at $D$ and $E$ respectively such that $AB = 7.2cm, AC = 6.4cm$ and $AD = 4.5cm$. Then, $AE =?$
  • A
    $5.4cm$
  • $4cm$
  • C
    $3.6cm$
  • D
    $3.2cm$

Answer: B.

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$ABC$ is an isosceles triangle, right-angled at $B$. Similar triangle $ACD$ and $ABE$ are constructed on sides $AC$ and $AB$. Find the ratio between the areas of $\triangle\text{ABE}$ and $\triangle\text{ACD}.$
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$\triangle\text{ABC}$ and $\triangle\text{DBC}$ lie on the same side of $BC$, as shown in the figure. From a point $P$ on $BC, PQ || AB$ and $PR || BD$ are drawn, meeting $AC$ at $Q$ and $CD$ at $R$ respectively. Prove that $QR || AD$.
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In a $\triangle\text{ABC},\text{AD}$ is a median and $\text{AL}\perp\text{BC}.$
Prove that:
  1. $\text{AC}^2=\text{AD}^2+\text{BC}.\text{DL}+\Big(\frac{\text{BC}}{2}\Big)^2$
  2. $\text{AB}^2=\text{AD}^2-\text{BC}.\text{DL}+\Big(\frac{\text{BC}}{2}\Big)^2$
  3. $\text{AC}^2+\text{AB}^2=2\text{AD}^2+\frac{\text{1}}{2}\text{BC}^2$
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Q 143 Marks Question3 Marks
$D$ and $E$ are points on the sides AB and AC respectively of a $\triangle\text{ABC}$ such that $DE || BC:$
$AD = (7x - 4)\ cm, AE = (5x - 2)\ cm, DB = (3x + 4)\ cm$ and $EC = 3x\ cm.$
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Q 153 Marks Question3 Marks
$D$ and $E$ are points on the sides $AB$ and $AC$ respectively of a $\triangle\text{ABC}.$ In the following cases, determine whether $DE || BC$ or not.
$AD = 7.2\ cm, AE = 6.4\ cm, AB = 12\ cm$ and $AC = 10\ cm.$
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In the given figure, if $\angle\text{ADE}=\angle\text{B},$ show that $\triangle\text{ADE}\sim\triangle\text{ABC}.$ If $AD = 3.8\ cm, AE = 3.6\ cm, BE = 2.1\ cm$ and $BC = 4.2\ cm$, find $DE.$
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$\triangle\text{ABC}$ is right-angled at $A$ and $\text{AD}\perp\text{BC}.$ If $BC = 13\ cm$ and $AC =5\ cm$, find the ratio of the areas of $\triangle\text{ABC}$ and $​​​​$$\triangle\text{ADC}.$
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A ladder is placed in such a way that its foot is at a distance of $15\ m$ from a wall and its top reaches a window $20\ m$ above the ground. Find the length of the ladder.
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