The highest number of helium atoms is in
- A$4$ u of helium
- B$4 \mathrm{~g}$ of helium
- C$2.271098 \mathrm{~L}$ of helium at $STP$
- ✓$4 \mathrm{~mol}$ of helium
Answer: D.
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Answer: D.
View full solution →(Given atomic masses of $A=64 ; B=40 ; C=32 u$ )
Answer: A.
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View full solution →Answer: A.
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