If $x=5 \sin \left(\pi t+\frac{\pi}{3}\right) \mathrm{m}$ represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are
- ✓$5 \mathrm{~m}, 2 \mathrm{~s}$
- B$5 \mathrm{~cm}, 1 \mathrm{~s}$
- C$5 \mathrm{~m}, 1 \mathrm{~s}$
- D$5 \mathrm{~cm}, 2 \mathrm{~s}$
Answer: A.
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