Questions

Answer the following (3 mark each)

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22 questions · timed · auto-graded

Question 13 Marks
A theatre company can accommodate 45 people during one show.
(a) A total of 475 people bought tickets for a puppet show. How many shows are needed to seat all the people who bought tickets?
(b) There are 2 shows in a day. How many days will be needed to accommodate all the people?
Answer
(a) The number of shows required for 475 people
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= 475 ÷ 45
Ten shows will accommodate 450 people and one more show will accommodate for the remaining 25 people.
Therefore, 11 shows are needed to seat all the people who bought tickets.
(b) From part (a) number of shows required is 11.
If there are 2 shows in a day, then in 5 days there will be 10 shows, and on 6th day the 11th show will be held.
Thus, 6 days are needed to accommodate all the people.
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Question 43 Marks
Solve the division:
3,005 ÷ 5
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Answer

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3005 = 3 Thousands + 0 hundreds + 0 tens + 5 ones.
3 Thousands ÷ 5 → not possible without regrouping
Regroup 3 thousands into hundreds.
30 hundreds
30 hundreds ÷ 5 = 6 hundreds
0 tens ÷ 5 = 0 tens
5 ones ÷ 5 = 1 ones
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Question 63 Marks
Tick in the appropriate cell for the following statements.
StatementAlways TrueSometimes TrueNever True
Adding 10 to a number gives a multiple of ten.   
Changing the order of the numbers in subtraction makes no difference.   
In multiplication, doubling one number and halving the other keeps the product the same.   
Multiplication by an odd number gives an even number.   
Multiplying a number by 5 leads to numbers which have '0' in the Ones place.   
Answer
StatementAlways TrueSometimes TrueNever True
Adding 10 to a number gives a multiple of ten.  
Changing the order of the numbers in subtraction makes no difference.  
In multiplication, doubling one number and halving the other keeps the product the same.  
Multiplication by an odd number gives an even number.  
Multiplying a number by 5 leads to numbers which have '0' in the Ones place.  
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Question 73 Marks
Think about the following statements and find examples as suggested below.
(a) “When two odd numbers are added, the sum is even.”
Find 5 examples for the above statement. Can you find an example to show that the statement can be false? Always true
(b) “Multiplying a number by 2 can give an odd number.”
Give some example for this statement. Can you find any? -Never true
(c) “Halving a number always leads to an even number.”
Give 3 examples for the statement. Can you find 3 examples when this is not true? -Sometimes true.
Answer
(a) Examples: 5 + 3 = 8, 9 + 5 = 14, 105 + 7 = 112, 11 + 13 = 24, 15 + 5 = 20, etc.
Since the statement is always true, we cannot find an example that the statement is false.
(b) Multiplying a number by 2 always gives an even number. So, the given statement is never true and hence we cannot find any such example to show that the given statement is true.
(c) Examples when statement is true:
$\frac{8}{2}=4, \frac{12}{2}=6, \frac{16}{2}=8, \frac{32}{2}=16$
Examples when statement is false:
$\frac{10}{2}=5, \frac{30}{2}=15, \frac{50}{2}=25, \frac{70}{2}=35$
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Question 83 Marks
To make one bookshelf, a carpenter needs the following things 4 long wooden panels 8 short wooden panels 16 small clips 4 large clips 32 screws
The carpenter has a stock of 264 long wooden panels, 306 short wooden panels, 2400 small clips, 120 large clips, and 2800 screws. How many bookshelves can the carpenter make? Discuss your thoughts.
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Answer
Since 264 ÷ 4 = 66
Therefore, the long wooden panels are sufficient for 66 bookshelves.
306 ÷ 8 = 38 and remainder 2.
So, the short wooden panels are sufficient 38 bookshelves.
2400 ÷ 16 = 150 and remainder 2.
So, the small clips are sufficient for 150 bookshelves
120 ÷ 4 = 30
So, large clips are sufficient for 30 bookshelves 2800 ÷ 32 = 87 and remainder 16.
So, screws are sufficient for 87 bookshelves. Based on the above data the carpenter can make 30 bookshelves.
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Question 93 Marks
Sofia has only ₹ 50 and ₹ 20 notes. She needs to pay ₹ 520 using these notes. How many ₹ 50 and ₹ 20 notes does she need to make ₹ 520? Find out the different possible combinations.
Answer
Let us check some possibilities by using division.
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So, 10 × ₹ 50 + 1 × ₹ 20 = ₹ 520
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So, 8 × ₹ 50 + 6 × ₹ 20 = ₹ 520
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So, 6 × ₹ 50 + 11 × ₹ 20 = ₹ 520
So, Sofia can pay using ten ₹ 50 notes and one ₹ 20 note, eight ₹ 50 notes and six ₹ 20 notes, or six ₹ 50 notes and eleven ₹ 20 notes.
There can be other possible combinations also.
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Question 103 Marks
Rani is planning to host a party. She estimates that 250 guests will attend. She plans to serve one samosa to each guest. Samosas are available in packs of 6 or 8. Which pack should Rani buy? Explain your answer.
Answer
Rani should choose the packs in such a way that the total number of samosas is not less than 250 but as close as possible to 250.
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So, 42 packs of samosas will have 252 samosas, and 32 packs of 8 samosas will have 256 samosas.
Here, 252 is closer to 250.
Therefore, Rani should buy samosas in pack of 6.
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Question 113 Marks
Place the numbers 1 to 8 in the following boxes so that all the four operations, division, multiplication, addition and subtraction are correct. No number must be repeated.
Is there more than one answer.
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Question 123 Marks
The owner of an electric store has decided to distribute ?5500 equally amongst 5 of his employees as a Diwali gift. What amount will each employee get?
What will happen if he distributes the same amount of money among 10 employees? Will each employee get more or less? How much money would he have to distribute if everyone must get the same amount as earlier?
Answer
If ₹ 5500 will be divided equally among 5 employees, then each employee will get:
5500 ÷ 5 = moo
If ₹ 5500 will be divided equally among 10 employees, then each employee will get:
5500 ÷ 10 = ₹ 550
Since, ₹ 550 < ₹ 1100, in this case each employee will get less.
To find the required amount to be distributed equally among 10 employees so that each employee can get ₹ 1100, we need to multiply 1100 by 10.
1100 × 10 =11000
Therefore, the required amount is ₹ 11000.
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Question 133 Marks
fill the place value chart.
ProblemHTO
110 ÷ 11 =
860 ÷ 86 =
7500 ÷ 750 =
8800 ÷ 88 =
2400 ÷ 24 =
440 ÷ 22 =
Answer
ProblemHTO
110 ÷ 11 = 10
860 ÷ 86 = 10
7500 ÷ 750 = 10
8800 ÷ 88 =100
2400 ÷ 24 =100
440 ÷ 22 = 20
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Question 143 Marks
fill the place value chart.
ProblemHTO
40 ÷ 10 = 4
400 ÷ 10 = 40
4000 ÷ 10 =400
700 ÷ 70 =
220 ÷ 20 =
2200 ÷ 20 =
Answer
ProblemHTO
40 ÷ 10 = 4
400 ÷ 10 = 40
4000 ÷ 10 =400
700 ÷ 70 = 14
220 ÷ 20 = 11
2200 ÷ 20 =110
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Question 153 Marks
Identify the numbers that can fill the circles such that the numbers in the squares are the products or the quotients of the numbers in the circles.
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Question 163 Marks
Rahul bought 6 kg of icecream for his 29 friends. After giving each friend an equal share, 200 g was left. How much icecream did each friend get?
Answer
200 g
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Question 173 Marks
A theatre hall has 60 seats. If 720 people come to watch a play, how many shows are required? If 3 shows are held in one day, how many days are needed to seat all the people?
Answer
12; 4
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Answer the following (3 mark each) - MATHS STD 5 Questions - Vidyadip