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Question 15 Marks
Answer
(a) 6
(b) 3
(c) VIII and IX
(d) VII
(e) No. of sections in class-VI = 6 and number of sections in class X = 3
Hence required ratio $=6/ 3 = 2/ 1$ = 2: 1
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Question 25 Marks
Answer
(a) Clearly from the bar graph, the maximum number of toys were produced on Monday = 200
(b) Clearly from the bar graph, the minimum number of toys were produced on Saturday = 40
(c) Clearly from the bar graph, number of toys produced on Tuesday = number of toys produced on Wednesday = 100
(d) Clearly from the bar graph, number of toys produced on Thursday =160 and number of toys produced on Friday =120
Hence required number of toys = 160 – 120 = 40
(e) Total number of toys produced during the week = 200 + 100 + 100 + 160 + 120 + 40 = 720
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5 Marks Questions - MATHS STD 6 Questions - Vidyadip