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Comparing Quantities · Gujarat Board (GSEB) STD 7 (GSEB - English Medium). 19 questions.

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Question 11 Mark
3500 is given at 7% p.a. rate of interest. Find the interest which will be received at the end of 2 yr.
Answer
Given, Principal, $P=$ ₹ $6050$; Rate of interest, $R=6.5 \%$
Time, $T=3 yr$
$\therefore$ Interest, $I=\frac{P \times R \times T}{100}=\frac{6050 \times 6.5 \times 3}{100}=\frac{117975}{100}$
$=$ ₹ $1179.75$
$\therefore$ Amount $=$ Principal + Interest
$=$ ₹ $6050+$ ₹ $1179.75=$ ₹ $7229.75$
Hence, the interest and amount at the end of 3 yr are ₹ $1179.75$ and ₹ $7229.75$, respectively.
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Question 21 Mark
75% of what number is 15?
Answer
Let the number be x.
$\therefore 75 \%$ of $x=15 \Rightarrow \frac{75}{100} \times x=15$
$\begin{array}{l}\Rightarrow x=15 \times \frac{100}{75} \\ \Rightarrow x=20\end{array}$
Hence, the number is 20.
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Question 31 Mark
9 is 25% of what number?
Answer
Let the number be x
$\therefore$ 25% of x = 9
$\Rightarrow \frac{25}{100} \times x=9 \Rightarrow \frac{x}{4}=9$
$\Rightarrow  x=9 \times 4 \Rightarrow x=36$
Hence, the number is 36.
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Question 41 Mark
Find
$12 \frac{1}{2} \%$ of 66
Answer
We have, $12 \frac{1}{2} \%$ of $64=\frac{25}{2} \%$ of $64\qquad$ $\left[\begin{array}{l}\text { converting the mixed fraction into } \\ \text { improper fraction i.e. } 12 \frac{1}{2}=\frac{25}{2}\end{array}\right]$
$=\frac{25}{2 \times 100} \times 64=\frac{1}{8} \times 64=8$
Hence, $12 \frac{1}{2} \%$ of 64 is 8 .
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Question 51 Mark
Find
75% of 12
Answer
We have, $75 \%$ of $12=\frac{75}{100} \times 12=\frac{3}{4} \times 12=3 \times 3=9$
Hence, 75% of 12 is 9.
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Question 71 Mark
Convert the following to per cents.
$\frac{2}{2}$
Answer
Given,
$\frac{2}{2}=\left(\frac{2}{2} \times 100\right) \%=(2 \times 50) \%=100 \%$
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Question 81 Mark
Convert the following to per cents.
3.5
Answer
Given,
$3.5=(3.5 \times 100) \%=\left(\frac{35}{10} \times 100\right) \%=350\%$
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Question 91 Mark
Convert the following to per cents.
$\frac{12}{16}$
Answer
Given,
$\frac{12}{16}=\left(\frac{12}{16} \times 100\right) \%=\left(\frac{1200}{16}\right) \%=75 \%$
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Question 101 Mark
Convert the following to per cents.
0.05
Answer
Given,
$0.05=(0.05 \times 100) \%=\left(\frac{5}{100} \times 100\right) \%=5 \%$
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Question 111 Mark
Convert the following to per cents.
$\frac{49}{50}$
Answer
Given,
$\frac{49}{50}=\left(\frac{49}{50} \times 100\right) \%=(49 \times 2) \%=98 \%$
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Question 121 Mark
Find out 8% of 25 kg.
Answer
Given,
8% of 25 kg
i.e.,$\frac{8}{100} \times 25$=$\frac{8 \times 25}{100}$=$\frac{8}{4}$=2kg
Hence, 8% of 25 kg is 2 kg
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Question 131 Mark
A box has 200 bulbs, out of which 10 are defective bulbs. What per cent are defective bulbs?
Answer
Total number of bulbs $=200$
Defective bulbs $=10$
$\therefore$ Percentage of defective bulbs = $\frac{10}{200} \times 100 \%=5\%$
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Question 141 Mark
Out of 32 students, 4 are absent. What per cent of students are absent?
Answer
Total number of students is 32 and 4 are absent
$\therefore\quad$Percentage of absent students
$\frac{4}{32} \times 100 \%$$=\frac{1}{8} \times 100 \%=12.5\%$
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Question 151 Mark
Express 150% as a ratio in the lowest form.
Answer
150% as a ratio in the lowest form is
$\frac{150}{100}=$$\frac{15}{10}=$$\frac{3}{2}$
Hence, the required ratio is 3 : 2
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Question 161 Mark
Convert 55% as a fraction
Answer
Given, 55%
For fraction,
$55 \times \frac{1}{100}=$$\frac{55}{100}=\frac{11}{20}$
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Question 171 Mark
Write following decimals as percentage.
(a) 6.1
(b) 0.064
Answer
(a) Given, 6.1
$\therefore 6.1 \times \frac{100}{100}$=$\frac{61}{10} \times 100 \%$
=$61 \times 10 \%$ = 610%
(b) Given, 0.064
$\therefore 0.064 \times \frac{100}{100}$=$\frac{64}{1000} \times 100 \%$
=$\frac{64}{10}$%=6.4%
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Question 181 Mark
Convert 0.02 in percentage
Answer
We have, 0.02
In percentage$\left(\frac{2}{100} \times 100\right) \%$=2%
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Question 191 Mark
Convert $\frac{35}{25}$in percentage.
Answer
We have,$\frac{35}{25}$
In percentage, $\frac{35}{25} \times 100=35 \times 4=$140%
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