Question 14 Marks
Answer
View full question & answer→(i) (a) By observing the graph, we have
Thus, game KC has $75 \%$ existing users which is more than 1.5 million.
Hence, KC is the game which has more than 1.5 million existing active users.
(ii) SN and HC are the games in which the number of new users is more than the number of existing users.
(iii) (c) RJ game has 50% existing users and 50% new users.
$\therefore$ The number of people in existing users and in new users $=50 \%$ of 20 million each
$
=\frac{50}{100} \times 20=10 \text { million each }
$
Now, the number of people playing RJ game online with friends
For new users $=\frac{50}{100} \times 10=5$ million
For existing users $=\frac{36}{100} \times 10$ million $=3.6$ million
$\therefore$ Total number of people playing RJ game online with friends $=5+3.6=8.6$ million
Thus, in the given options 8.557 million is approximate to 8.6 million.
Hence, the required answer is 8.557 million.
(iv)(d) Mary played 10 HC matches. She scored $45,36,50,27,36,52,50,43,50$ and $47$ points in them.
Given, data in tabular form is as follows
From the above table we can easily say that the point 50 occurs most frequently i.e. 3 times.
Hence, 50 is the most frequent score point.
| Games | Existing users (in percentage) | New users (in percentage) |
| KC | 75 | 25 |
| RJ | 50 | 50 |
| CM | 65 | 35 |
| SN | 45 | 55 |
| CR | 60 | 40 |
| HC | 40 | 60 |
Hence, KC is the game which has more than 1.5 million existing active users.
(ii) SN and HC are the games in which the number of new users is more than the number of existing users.
(iii) (c) RJ game has 50% existing users and 50% new users.
$\therefore$ The number of people in existing users and in new users $=50 \%$ of 20 million each
$
=\frac{50}{100} \times 20=10 \text { million each }
$
Now, the number of people playing RJ game online with friends
For new users $=\frac{50}{100} \times 10=5$ million
For existing users $=\frac{36}{100} \times 10$ million $=3.6$ million
$\therefore$ Total number of people playing RJ game online with friends $=5+3.6=8.6$ million
Thus, in the given options 8.557 million is approximate to 8.6 million.
Hence, the required answer is 8.557 million.
(iv)(d) Mary played 10 HC matches. She scored $45,36,50,27,36,52,50,43,50$ and $47$ points in them.
Given, data in tabular form is as follows
| Points | Tally marks | Number of times |
| 27 | ∣ | 1 |
| 36 | || | 2 |
| 43 | ∣ | 1 |
| 45 | ∣ | 1 |
| 47 | ∣ | 1 |
| 50 | III | 3 |
| 52 | ∣ | 1 |
| Total | 10 |
Hence, 50 is the most frequent score point.