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MATHS M.C.Q. [1 Marks Each]

Data Handling · Gujarat Board (GSEB) STD 7 (GSEB - English Medium). 15 questions.

Questions

M.C.Q. [1 Marks Each]

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15 questions · auto-graded multiple-choice test.

MCQ 11 Mark
The number of trees in different parks of a city are $33,38,48,33,34,34,33$ and 24 . The mode of this data is
  • A
    24
  • B
    34
  • ✓
    33
  • D
    48
Answer
Correct option: C.
33
C
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MCQ 21 Mark
Let $x, y$ and $z$ be three observations. The mean of these observations is
  • A
    $\frac{x \times y \times z}{3}$
  • ✓
    $\frac{x+y+z}{3}$
  • C
    $\frac{x-y-z}{3}$
  • D
    $\frac{x \times y+z}{3}$
Answer
Correct option: B.
$\frac{x+y+z}{3}$
B
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MCQ 31 Mark
Khilona earned scores of 97, 73 and 88, respectively in her first three examinations. If she scored $8 0$ in the fourth examination, then her average score will be
  • A
    increased by 1
  • B
    increased by 1.5
  • C
    decreased by 1
  • ✓
    decreased by 1.5
Answer
Correct option: D.
decreased by 1.5
(D). decreased by 1.5
$\because$ Average score of Khilona for first three examinations
$
=\frac{97+73+88}{3}=86
$
Her average score for all four examinations
$
\begin{array}{l}
=\frac{97+73+88+80}{4}=\frac{258+80}{4} \\
=84.5
\end{array}
$
$
\because 86>84.5
$
$\Rightarrow$ score decreased
Difference $=86-84.5=1.5$
Hence, Khilona's average score decreased by 1.5
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MCQ 41 Mark
Which measures of central tendency get affected, if the extreme observations on both the ends of a data arranged in descending order are removed?
  • ✓
    Mean and mode
  • B
    Mean and median
  • C
    Mode and median
  • D
    Mean, median and mode
Answer
Correct option: A.
Mean and mode
A
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MCQ 51 Mark
The mean of three numbers is 40 . All the three numbers are different natural numbers. If lowest is 19, what could be the heighest possible number of remaining two numbers?
  • ✓
    81
  • B
    40
  • C
    100
  • D
    71
Answer
Correct option: A.
81
(A). 81
We know,
$
\text { Mean }=\frac{\text { Sum of observations }}{\text { Number of observation }}
$
Let the remaining two numbers be $x$ and $y$.
$\therefore$ Sum of observations $=19+x+y$
Number of observation $=3$
$
\begin{array}{ll}
\therefore & 40=\frac{19+x+y}{3} \Rightarrow 19+x+y=120 \\
\Rightarrow & x+y
\end{array}
$
Let the heighest number be $y$.
Then, $y=101-x$
Since, the lowest number is $19, x$ can't be less than 19.
i.e. $x>19$
Let $x=20$, then $y=101-20=81$
Therefore, the highest number is 81 .
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MCQ 61 Mark
The mode of the following data is 2,3,5,7,5,4,5,3,3,8,2
  • A
    2 and 3
  • ✓
    3 and 5
  • C
    4 and 5
  • D
    only 3
Answer
Correct option: B.
3 and 5
(B). 3 and 5
Given data is $ 2,3,5,7,5,4,5,3,3,8,2 $ From the above data, it is clear that 3 and 5 has occured maximum number of times i.e. 3.
Hence, the mode of data are 3 and 5.
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MCQ 91 Mark
The marks (out of 100) obtained by a group of students in a Maths test are 82, 87, 92, 72, 83. The range of the marks obtained is
  • A
    8
  • B
    11
  • C
    5
  • ✓
    20
Answer
Correct option: D.
20
D
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MCQ 101 Mark
The difference between the highest and the lowest observations in a data is its
  • A
    frequency
  • B
    width
  • ✓
    range
  • D
    mode
Answer
Correct option: C.
range
C
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MCQ 111 Mark
If the arithmetic mean of $18,16, x, 12,6,0$ and 70 is 18 , then the value of $x$ is
  • A
    2
  • B
    16
  • ✓
    4
  • D
    17
Answer
Correct option: C.
4
(C). 4
Given, observations are $18,16, x, 12,6,0$ and 70
and mean $=18$
$
\begin{array}{l}
\text { Now, sum of observations }=18+16+x+12+6+0+70 \\
=122+x \\
\therefore \quad 18=\frac{122+x}{7} \\
\Rightarrow 122+x=126 \\
\Rightarrow \quad x=126-122=4
\end{array}
$
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MCQ 121 Mark
The mean of the first 15 whole numbers is
  • A
    6
  • B
    8
  • ✓
    7
  • D
    7.5
Answer
Correct option: C.
7
(C). 7
We know that whole numbers are those which starts from zero (0).
So, first 15 whole numbers are
$
\begin{array}{c}
0,1,2,3,4,5,6,7,8,9,10,11,12,13,14 \\
\therefore \text { Mean }=\frac{\text { Sum of numbers }}{\text { Number of terms }} \Rightarrow \text { Mean }=\frac{105}{15}=7
\end{array}
$
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MCQ 131 Mark
If mean and sum of $n$ observations are 29 and 174 respectively, then $n$ is equal to
  • A
    4
  • ✓
    6
  • C
    8
  • D
    5
Answer
Correct option: B.
6
(B). 6
We know,
$
\begin{aligned}
\text { Mean } & =\frac{\text { Sum of all observations }}{\text { Number of observations }} \\
\Rightarrow \quad 29 & =\frac{174}{n} \Rightarrow n=\frac{174}{29}=6
\end{aligned}
$
Hence, number of observation $n=6$.
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MCQ 141 Mark
The money saved by a student during first six days of a week are ₹ 46 , ₹ 24, ₹ 29, ₹ 27, ₹ 42 and ₹ 42 . Find the average saving per day.
  • A
    42
  • B
    39
  • ✓
    35
  • D
    36
Answer
Correct option: C.
35
(C). 35
Average saving money per day
$=\frac{\text { Sum of saved money of all six days }}{\text { Number of days }} $
$=\frac{46+24+29+27+42+42}{6} $
$=\frac{210}{6}=$$$ ₹ $35$
Hence, the average saving of student per day is ₹35.
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MCQ 151 Mark
If mean of 6 observations is 4 , then their sum is
  • A
    20
  • B
    22
  • ✓
    24
  • D
    26
Answer
Correct option: C.
24
(C). 24
Let sum of all 6 observations be $x$.
$
\begin{array}{l}
\text { Then, mean }=\frac{\text { Sum of all observations }}{\text { Number of observations }} \\
\Rightarrow \quad 4=\frac{x}{6} \quad \text { [given, mean }=4 \text { ] } \\
\Rightarrow \quad x=24
\end{array}
$
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M.C.Q. [1 Marks Each] - MATHS STD 7 Questions - Vidyadip