MATHS MCQ

In the given figure,
∆ABC = ∆PQR
∠A = ∠P and ∠B = ∠Q
Now x – 7 = 70°
⇒ x = 70° + 7 = 77°
and 2y + 5 = 75
⇒ 2y = 75° – 5 = 70°
⇒ y = 35°
x = 77°, y = 35° (b)

In the given two triangles are not congruent.
In first triangle, AAS are given while in second ASA are given. (d)

In the given figure, M is mid-point of AC and BD both then ∠1 = ∠4. (b)

Correct statement is ∆ABC = ∆QRP. (b)

If ∆ABC = ∆PQR by SAS
BC = QR and ∠C = ∠R, then AC = PR (a)

In ∆DEF = ∆PQR
∠D = ∠P, ∠E = ∠Q
DE = PQ
∆DEF = ∆PQR (ASA axiom) (b)

∆ABC = ∆PQR

Then AB = PQ
AC = PR (d)

∆ABC = ∆PQR

∠CAB = 65°
∠RPQ = 65° (corresponding angles) (a)

The axiom SSA is not a standard criterion of congruency of triangles. (b)