Question 12 Marks
In the figure $,\text{AB} =\text{EF}, \text{BC} = \text{DE}, \text{AB}$ and $\text{FE}$ are perpendiculars on $\text{BE}.$ Prove that $\triangle ABD ≅ \triangle FEC$
Answer
View full question & answer→In $\triangle ABD$ and $\triangle FEC$
$\text{AB} = \text{FE}$
$\text{BD} = \text{CE} ...(\text{BC} =\text{DE}; {CD}$ is common$)$
$\angle B = \angle E$
$\triangle ABD ≅ \triangle FEC ...(\text{SAS}$ criteria$).$
$\text{AB} = \text{FE}$
$\text{BD} = \text{CE} ...(\text{BC} =\text{DE}; {CD}$ is common$)$
$\angle B = \angle E$
$\triangle ABD ≅ \triangle FEC ...(\text{SAS}$ criteria$).$