Question types

Triangles and their congruency question types

51 questions across 4 question groups — pick any mix to generate a MATHEMATICS paper with step-by-step answer keys.

51
Questions
4
Question groups
5
Question types
Sample Questions

Triangles and their congruency questions

One sample from each question group in this chapter. Select any group above to see the full set with answer keys.

Q 3[3 marks sum]3 Marks
In the figure, $\angle CPD = \angle BPD$ and $AD$ is the bisector of $\angle BAC.$ Prove that $\triangle CAP ≅ \triangle BAP$ and $CP = BP.$
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Q 4[3 marks sum]3 Marks
In $\triangle ABC$ and $\triangle PQR$ and, $AB = PQ, BC = QR$ and $CB$ and $RQ$ are extended to $X$ and $Y$ respectively and $\angle ABX = \angle PQY. =$ Prove that $\triangle ABC ≅ \triangle PQR.$
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Q 5[3 marks sum]3 Marks
In $\triangle ABC, AD$ is a median. The perpendiculars from $B$ and $C$ meet the line $AD$ produced at $X$ and $Y$. Prove that $BX = CY.$
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Q 8[4 marks sum]4 Marks
$\text{PQRS}$ is a quadrilateral and $T$ and $U$ are points on $PS$ and $RS$ respectively such that $PQ = RQ, ∠PQT = ∠RQU$and $∠TQS = ∠UQS$. Prove that $QT = QU.$
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Q 10[4 marks sum]4 Marks
$\triangle ABC$ is an isosceles triangle with A$B = AC. GB$ and $HC ARE$ perpendiculars drawn on $BC.$

​​​​​​​Prove that
$(i) BG = CH$
$(ii) AG = AH$
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Q 11[4 marks sum]4 Marks
$O$ is any point in the $\triangle ABC$ such that the perpendicular drawn from $O$ on $AB$ and $AC$ are equal. Prove that $OA$ is the bisector of $\angle BAC.$
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Q 12[5 marks sum]5 Marks
In $\triangle ABC, AB = AC$ and the bisectors of angles $B$ and $C$ intersect at point $O$.Prove that $BO = CO$ and the ray $AO$ is the bisector of $\angle BAC.$
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Q 13[5 marks sum]5 Marks
In a $\triangle ABC$, if $D$ is midpoint of $BC; AD$ is produced upto $E$ such as $DE = AD$, then prove that:$a. \text{DABD}$ and $\text{DECD}$ are congruent.$b. AB = EC,c. AB$ is parallel to $EC$
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Q 16[5 marks sum]5 Marks
In the given figure $\text{ABCD}$ is a parallelogram, $AB$ is Produced to $L$ and $E$ is a midpoint of $BC$. Show that:

$a. \text{DDCE} \cong \text{DLDE};b. A B=B L;c. DC =\frac{ AL }{2}$
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