Question 12 Marks
A spaceship is moving in space with a velocity of $60 kms ^{-1}$. It fires its retro engines for 20 second and velocity is reduced to $55 kms ^{-1}$. Calculate the distance travelled by the spaceship in 40 s , from the time of firing of the retro- rockets.
Answer
View full question & answer→Initial velocity of spaceship $= u =60 kms ^{-1}$
Final velocity of spaceship $=v=55 kms^{-1}$
Case -1:
It decelerates for 20 s
$
\begin{array}{l}
\Rightarrow t=20 s \\
v=u+a t \\
55=60+a(20) \\
20 a=55-60=-5
\end{array}
$
Final velocity of spaceship $=v=55 kms^{-1}$
Case -1:
It decelerates for 20 s
$
\begin{array}{l}
\Rightarrow t=20 s \\
v=u+a t \\
55=60+a(20) \\
20 a=55-60=-5
\end{array}
$
