Download App

Chemistry 5 Marks Questions

General Principles and Processes of Isolation of Elements · Jharkhand Board (JAC) STD 12 Science (Jharkhand - English Medium). 5 questions.

Questions

5 Marks Questions

Take a timed test

5 questions · self-marked practice — reveal the answer and mark yourself.

Question 15 Marks
Match the items of Column I with items of Column II and assign the correct code:
 
Column I
 
Column II
$(A)$
Pendulum
$(1)$
Chrome steel
$(B)$
Malachite
$(2)$
Nickel steel
$(C)$
Calamine
$(3)$
$Na_3AlF_6$
$(D)$
Cryolite
$(4)$
$CuCO_3.Cu (OH)_2$
 
 
$(5)$
$ZnCO_3$
  1. $A (1) B (2) C (3) D (4)$
  2. $A (2) B (4) C (5) D (3)$
  3. $A (2) B (3) C (4) D (5)$
  4. $A (4) B (5) C (3) D (2)$
Answer
 
Column I
 
Column II
$(A)$
Pendulum
$(2)$
Nickel steel
$(B)$
Malachite
$(4)$
$CuCO_3.Cu (OH)_2$
$(C)$
Calamine
$(5)$
$Na_3AlF_6ZnCO_3$
$(D)$
Cryolite
$(3)$
$Na_3AlF_6$
  1. $A (2) B (4) C (5) D (3)$
Explanation:
  1. Pendulum is made up of nickel steel
  2. Malachite$-\ CuCO_3\ Cu\ (OH)_2$
  3. Calamine$-\ ZnCO_3$
  4. Cryolyte$-\ Na_3AlF_6$
View full question & answer→
Question 25 Marks
Match the items of Column I with items of Column II and assign the correct code:
 
Column I
 
Column II
(A)
 Cyanide process
(1)
 Ultrapure Ge
(B)
 Froth Floatation process
(2)
 Dressing of ZnS
(C)
 Electolytic reduction
(3)
 Extraction of Al
(D)
 Zone refinning
(4)
 Extraction of Au
 
 
(5)
 Purification of Ni
  1. A (4) B (2) C (3) D (1)
  2. A (2) B (3) C (1) D (5)
  3. A (1) B (2) C (3) D (4)
  4. A (3) B (4) C (5) D (1)
Answer
 
Column I
 
Column II
(A)
 Cyanide process
(4)
 Extraction of Au
(B)
 Froth Floatation process
(2)
 Dressing of ZnS
(C)
 Electolytic reduction
(3)
 Extraction of Al
(D)
 Zone refinning
(1)
 Ultrapure Ge
  1. A (4) B (2) C (3) D (1)
Explanation:
  1. For the extraction of Au, cyanide process is used.
  2. Froth floation process is used for sulphide ore like for ZnS.
  3. Electrolytic reduction can be used for the extraction of Al.
  4. Zone refining is used for ultrapure Ge.
View full question & answer→
Question 35 Marks
Match the items of Column I with items of Column II and assign the correct code:
 
Column I
 
Column II
$(A)$
Sapphire
$(1)$
$Al_2O_3$
$(B)$
Sphalerite
$(2)$
$NaCN$
$(C)$
Depressant
$(3)$
$CO$
$(D)$
Corundum
$(4)$
$ZnS$
 
 
$(5)$
$Fe_2O_3$
  1. $A (3) B (4) C (2) D (1)$
  2. $A (5) B (4) C (3) D (2)$
  3. $A (2) B (3) C (4) D (5)$
  4. $A (1) B (2) C (3) D (4)$
Answer
 
Column I
 
Column II
$(A)$
Sapphire
$(3)$
$CO$
$(B)$
Sphalerite
$(4)$
$ZnS$
$(C)$
Depressant
$(2)$
$NaCN$
$(D)$
Corundum
$(1)$
$Al_2O_3$
  1. $A (3) B (4) C (2) D (1)$
Explanation:
  1. Sapphire is a gemstone which contains $Co.$
  2. Molecular formula of sphalerite is $ZnS.$
  3. $NaCN$ is used as a depressant in froth floatation method.
  4. Molecular formula of corundum is $Al_2O_3.$
View full question & answer→
Question 45 Marks
Match the items of Column I with items of Column II and assign the correct code:
 
Column I
 
Column II
(A)
Coloured bands
(1)
Zone refining
(B)
LImpure matal to volatie complex
(2)
Fractional distillation
(C)
Purification of Ge and Si
(3)
Mond process
(D)
Purification of mercury
(4)
Chromatophy
 
 
(5)
Liquation
  1. A (1) B (2) C (4) D (5)
  2. A (4) B (3) C (1) D (2)
  3. A (3) B (4) C (2) D (1)
  4. A (5) B (4) C (3) D (2)
Answer
 
Column I
 
Column II
(A)
Coloured bands
(4)
Chromatophy
(B)
LImpure matal to volatie complex
(3)
Mond process
(C)
Purification of Ge and Si
(1)
Zone refining
(D)
Purification of mercury
(2)
Fractional distillation
  1. A (4) B (3) C (1) D (2)
Explanation:
  1. Coloured bands are observed in chromatography.
  2. Impure metal is converted to volatile complex by using Mond’s process.
  3. Ge and Si are purified by zone refining method.
  4. Purification of mercury is done by fractional distillation.
View full question & answer→
Question 55 Marks
Match the items of Column I with items of Column II and assign the correct code:
 
Column I
 
Column II
(A)
Blisterred Cu
(1)
Aluminium
(B)
Blast furnace
(2)
$2\text{Cu}_{2}\text{O}+\text{Cu}_{2}\text{S}\ \xrightarrow{\ \ \ \ \ }6\text{Cu}+\text{SO}_{2}$
(C)
Reveerberatory furnace
(3)
Iron
(D)
Hall - Hereoult proess
(4)
$\text{FeO}+\text{SiO}_{2}\ \xrightarrow{\ \ \ \ \ }\text{FeSiO}_{3}$
 
 
(5)
$2\text{Cu}_{2}\text{S}+3\text{O}_{2}\ \xrightarrow{\ \ \ \ \ }2\text{Cu}_{2}\text{O}+2\text{SO}_{2}$
  1. A (2) B (3) C (4) D (1)
  2. A (1) B (2) C (3) D (5)
  3. A (5) B (4) C (3) D (2)
  4. A (4) B (5) C (3) D (2)
Answer
 
Column I
 
Column II
(A)
Blisterred Cu
(1)
 $2\text{Cu}_{2}\text{O}+\text{Cu}_{2}\text{S}\ \xrightarrow{\ \ \ \ \ }6\text{Cu}+\text{SO}_{2}$
(B)
Blast furnace
(2)
Iron
 
(C)
Reveerberatory furnace
(3)
$\text{FeO}+\text{SiO}_{2}\ \xrightarrow{\ \ \ \ \ }\text{FeSiO}_{3}$
(D)
Hall - Hereoult proess
(4)
Aluminium
 
  1. A (2) B (3) C (4) D (1)
Explanation:
  1. Blistered Cu can be prepared by means of the following chemical reaction:
$2\text{Cu}_{2}\text{O}+\text{Cu}_{2}\text{S}\ \xrightarrow{\ \ \ \ \ \ }6\text{Cu}+\text{SO}_{2}$
  1. Iron is extracted in the blast furnace.
  2. In reverbereatory funace, the formation of slag occurs as
$\text{FeO}+\text{SiO}_{2}\ \xrightarrow{\ \ \ \ \ \ }\text{FeSiO}_{3}$
View full question & answer→
Generate Paper FreeAll General Principles and Processes of Isolation of Elements topics