A bag contains $4$ green balls, $4$ red balls and $2$ blue balls. If a ball is drawn from the bag, the probability of getting neither green nor red ball is:
- A$\frac{2}{5}$
- B$\frac{1}{2}$
- C$\frac{4}{5}$
- ✓$\frac{1}{5}$
Answer: D.
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