Questions

M.C.Q. [1 Marks Each]

Take a timed test

10 questions · auto-graded multiple-choice test.

MCQ 11 Mark
A bag contains $4$ green balls, $4$ red balls and $2$ blue balls. If a ball is drawn from the bag, the probability of getting neither green nor red ball is:
  • A
    $\frac{2}{5}$
  • B
    $\frac{1}{2}$
  • C
    $\frac{4}{5}$
  • $\frac{1}{5}$
Answer
Correct option: D.
$\frac{1}{5}$
The probability of getting neither green nor red ball is equal to the probability of getting blue balls.
Number of blue balls $= 2$
Total number of balls $= 4 + 4 + 2 = 10$
Therefore
Probability of getting neither green nor red ball $=\frac{2}{10}=\frac{1}{5}$
Hence, the correct option is $(d).$
View full question & answer
MCQ 21 Mark
There are $10$ cards numbered from $1$ to $10.$ A card is drawn randomly. The probability of getting an even numbered card is:
  • A
    $\frac{1}{10}$
  • B
    $\frac{1}{5}$
  • $\frac{1}{2}$
  • D
    $\frac{2}{5}$
Answer
Correct option: C.
$\frac{1}{2}$
The number on the cards are $1, 2, 3, 4, 5, 6, 7, 8, 9, 10,$
The even numbers on the cards are $2, 4, 6, 8, 10,$
$\therefore $ Probability of getting an even numbered card $=\frac{\text{Number of even numbered card}}{\text{Number of cards with numbers from 1 to 10}}=\frac{5}{10}=\frac{1}{2}$
Hence, the correct option is $(c).$
View full question & answer
MCQ 31 Mark
A dice is rolled. The probability of getting an even prime is:
  • $\frac{1}{6}$
  • B
    $\frac{1}{3}$
  • C
    $\frac{1}{2}$
  • D
    $\frac{5}{6}$
Answer
Correct option: A.
$\frac{1}{6}$
The possible numbers on a dice are $1, 2, 3, 4, 5, 6.$
There is only one even prime number which is $2.$
$\therefore$ Probability of getting an even prime $ =\frac{\text{Number of even prime numbers}}{\text{Number of all possible outcomes on the dice}}=\frac{1}{6}$
Hence, the correct option is $(a).$
View full question & answer
MCQ 41 Mark
A dice is tossed $80$ times and number $5$ is obtained $14$ times. The probability of not getting the number $5$ is:
  • A
    $\frac{7}{40}$
  • B
    $\frac{7}{80}$
  • $\frac{33}{40}$
  • D
    None of thesee
Answer
Correct option: C.
$\frac{33}{40}$
Probability of getting $5=\frac{14}{80}=\frac{7}{40}$
Therefore
Probability of not getting $5=1-\frac{7}{40}=\frac{33}{40}$
Hence, the correct option is $(c).$
View full question & answer
MCQ 51 Mark
There are $100$ cards numbered from $1$ to $100$ in a box. If a card is drawn from the box and the probability of an event is $\frac{1}{2},$ then the number of favourable cases to the event is:
  • A
    $20$
  • B
    $25$
  • C
    $40$
  • $50$
Answer
Correct option: D.
$50$
Here, $\frac{50}{100}=\frac{1}{2}$
So, if the the probability of an event is $\frac{1}{2},$ then the number of favourable cases has to be $50.$
Hence, the correct option is $(d).$
View full question & answer
MCQ 61 Mark
There are $10$ marbles in a box which are marked with the distinct numbers from $1$ to $10$. A marble is drawn randomly. The probability of getting prime numbered marble is:
  • A
    $\frac{1}{2}$
  • $\frac{2}{5}$
  • C
    $\frac{9}{3}$
  • D
    $\frac{3}{10}$
Answer
Correct option: B.
$\frac{2}{5}$
The numbers marked on the marbles are $1, 2, 3, 4, 5, 6, 7, 8, 9,$ and $10.$
Here, the prime numbers (favourable outcomes) are $2, 3, 5,$ and $7.$
$\therefore$ Number of favourable outcomes $= 4$
Therefore
Probability of getting prime numbered marble $=\frac{4}{10}=\frac{2}{5}$
Hence, the correct option is $(b).$
View full question & answer
MCQ 71 Mark
The probability of getting a red card from a well shuffled pack of cards is:
  • A
    $\frac{1}{4}$
  • $\frac{1}{2}$
  • C
    $\frac{3}{4}$
  • D
    $\frac{1}{3}$
Answer
Correct option: B.
$\frac{1}{2}$
There are $52$ cards in a standard deck. There are four different suits Diamonds (red), Clubs (black), Hearts (red), and Spades (black) each containing $13$ cards.
$\therefore $ Number of red cards $($favourable outcomes$) = 13 + 13 = 26$
Therefore
Probability of getting a red card $=\frac{26}{52}=\frac{1}{2}$
Hence, the correct option is $(b).$
View full question & answer
MCQ 81 Mark
A coin is tossed $100$ times and head is obtained $59$ times. The probability of getting a tail is:
  • A
    $\frac{59}{100}$
  • $\frac{41}{100}$
  • C
    $\frac{29}{100}$
  • D
    $\frac{43}{100}$
Answer
Correct option: B.
$\frac{41}{100}$
Number of all possible outcomes $= 100$
Number of head obtained $= 59$
Number of tail obtained $($favourable outcomes$) = 100 - 59 = 41$
Therefore
Probability of getting a tail $\frac{41}{100}$
Hence, the correct option is $(b).$
View full question & answer
MCQ 91 Mark
An unbiased coin is tossed once, the probability of getting head is:
  • $\frac{1}{2}$
  • B
    $1$
  • C
    $\frac{1}{3}$
  • D
    $\frac{1}{4}$
Answer
Correct option: A.
$\frac{1}{2}$
Tossing a coin, either we get a head $(H)$ or a tail $(T).$
So, the probability of getting a head is $\frac{1}{2}$
Hence, the correct option is $(a).$
View full question & answer
MCQ 101 Mark
When a dice is thrown, the total number of possible outcomes is:
  • $6$
  • B
    $1$
  • C
    $3$
  • D
    $4$
Answer
Correct option: A.
$6$
The number on the faces of a dice are $1, 2, 3, 4, 5,$ and $6.$
$\therefore$ Number of possible outcomes $= 6.$
Hence, the correct option is $(a).$
View full question & answer