Question 11 Mark
________ $\div 48 = –1$
AnswerWe have,
________ $\div 48 = - 1$
Here,
$x \div 48 = - 1$
$x = (-1)(48) = -48$
View full question & answer→Question 21 Mark
________ $\div 1 = – 87$
AnswerWe have,
$ _\_\_\_\_\_ \div 1 = - 87$
$$Here, $x \div 1 = - 87$
$x = (-87)(1) = -87$
View full question & answer→Question 31 Mark
$– 87 \div \_\_\_\_\_\_\_\_\ = 87$
AnswerWe have,
$- 87 \div \_\_\_\_\_\_\_\_\ = 87$
So,
$- 87 \div x = 87$
$x = - 87 / 87 = -1$
View full question & answer→Question 41 Mark
$(–206) \div _\_\_\_\_\_\_\_\ = 1$
AnswerWe have,
$(-206) \div \_\_\_\_\_\_\_\_\ = 1$
Here,$ (-206) \div x = 1$
$x = -206 / 1 = -206$
$$
View full question & answer→Question 51 Mark
$(–75) \div \_\_\_\_\_\_\_\_= –1$
AnswerWe have,
$(-75) \div \_\_\_\_\_\_\_\_\ = - 1$
So,
$(-75) \div x = - 1$
$x = -75 / -1$
$x = 75$
View full question & answer→Question 61 Mark
$369 \div \_\_\_\_\_\_\_\_\ = 369$
AnswerWe have,
$369 \div \_\_\_\_\_\_ = 369$
So,
$369 \div 1 = 369$ [Dividing/Multiplying to a number by $1$ gives the same number]
View full question & answer→Question 71 Mark
Evaluate [$(- 6) \div 5)] \div [(- 2) + 1]$
Answer$[(- 6) \div 5)] \div [(- 2) + 1]$
$= (- 1) \div (- 1)$
$= \frac {-1}{-1} $
$= 1$
View full question & answer→Question 81 Mark
Evaluate: $[(-36) \div 12] \div 3$
Answer$[(-36) \div 12] \div 3$
$= [-3] \div 3$
$= [-1]$
View full question & answer→Question 91 Mark
Evaluate $(- 31) \div [(–30) + (- 1)]$
Answer$(- 31) \div [(–30) + (- 1)]$
$= (- 31) \div (- 31)$
$= \frac {-31}{-31} $
$= 1$
View full question & answer→Question 101 Mark
Evaluate $0 \div (-12)$
Answer$0 $$\div$$ (- 12)$
= $\frac {0}{-12}$
$= 0$
View full question & answer→Question 111 Mark
Evaluate $13 \div [(- 2) + 1]$
Answer$13 \div [(- 2) + 1]$
$= 13 \div (- 1)$
$= \frac {13}{-1} $
$= - 13$
View full question & answer→Question 121 Mark
Evaluate $(- 49) \div (49)$
Answer$(- 49) \div (49)$
$= \frac {-49}{49} $
$= -1$
View full question & answer→Question 131 Mark
Evaluate $(- 36) \div (- 9)$
Answer$(- 36) \div (- 9)$
$= \frac {-36}{-9} $
$= 4$
View full question & answer→Question 141 Mark
Evaluate $50 \div (- 5)$
Answer$50 \div (- 5)$
$= \frac {50}{-5} $
$= - 10$
View full question & answer→Question 151 Mark
Evaluate $(- 30) \div 10$
Answer$(- 30) \div 10$
$= \frac {-30}{10} $
$= - 3$
View full question & answer→Question 161 Mark
Determine the integer whose product with $(–1)$ is $0$
AnswerWe have,
$a \times (-1) = 0$
$a = \frac{0}{-1} = 0$
View full question & answer→Question 171 Mark
Determine the integer whose product with $(–1)$ is $37$
AnswerAccording to question,
$- 1 \times a = 37$
So, $a = -37$
View full question & answer→Question 181 Mark
Determine the integer whose product with $(–1)$ is $–22$
Answer$(–1) \times 22 = (-22)$
View full question & answer→Question 191 Mark
For any integer a, what is $(–1) \times$ a equal to?
Answer$(–1) \times a = –a$
View full question & answer→Question 201 Mark
$(-1) \times(-2) \times(-3) \times 4$
Answer$(-1) \times(-2) \times(-3) \times 4=(-6 \times 4)=-24$
View full question & answer→Question 211 Mark
$(-18) \times(-5) \times(-4)$
Answer$(-18) \times(-5) \times(-4)=90 \times(-4)=-360$
View full question & answer→Question 221 Mark
$9 \times(-3) \times(-6)$
Answer$9 \times(-3) \times(-6)=9 \times 18=162$
View full question & answer→Question 231 Mark
$(-12) \times(-11) \times(10)$
Answer$(-12) \times(-11) \times(10)=132 \times 10=1320$
View full question & answer→Question 241 Mark
$(-15) \times 0 \times(-18)$
Answer$(-15) \times 0 \times(-18)=0$
View full question & answer→Question 251 Mark
$(-316) \times(-1)$
Answer$(-316) \times(-1)=316$
View full question & answer→Question 261 Mark
$(-21) \times(-30)$
Answer$(-21) \times(-30)=630$
View full question & answer→Question 271 Mark
$(-1) \times 225$
Answer$(-1) \times 225=-225$
View full question & answer→Question 281 Mark
$(-3) \times(-6) \times(-2) \times(-1)$
Answer$(-3) \times(-6) \times(2) \times(-1)=(-18) \times(-2)=36$
View full question & answer→Question 291 Mark
$3 \times(-1)$
View full question & answer→Question 301 Mark
$17 + \_\_\_\_\_\_\_\_ = 0$
AnswerWe have, $17 + $________ $= 0$
We know if we add the negative of the number itself it will give zero,
So, $17 + (-17) = 0$
View full question & answer→Question 311 Mark
$-53 + $________$ = -53$
AnswerWe have, $- 53 + $________$ = - 53$
As, $0$ is the number which is added to a number to give the same number.
So, $- 53 + (0) = - 53$
View full question & answer→Question 321 Mark
$(–5) + (– 8) = (– 8) + ($________$)$
View full question & answer→Question 331 Mark
Write a negative integer and a positive integer whose difference is $-3.$
AnswerNegative integer and positive integer having difference $- 3$ is as follows:
$- 2 - (1) = - 2 – 1 = - 3$
So the two integers are $-2$ and $1$ respectively.
View full question & answer→Question 341 Mark
Write a negative integer and a positive integer whose sum is $–5.$
Answer$(–10)$ and $5 \left(-10\right)+5=-5$
View full question & answer→Question 351 Mark
Write a pair of negative integers whose difference gives $8.$
Answer$(–10)$ and $(–18) \left(-10\right)-\left(-18\right)=-10+18=8$
View full question & answer→Question 361 Mark
Write a pair of integers whose sum is $0.$
Answer$(–49)$ and $49(-49)+49=0 $
View full question & answer→Question 371 Mark
Write a pair of integers whose difference is $–10.$
Answer$15$ and $25 15-25=\left(-10\right)\;$
View full question & answer→Question 381 Mark
A shopkeeper earns a profit of $₹ 1$ by selling one pen and incurs a loss of $40$ paise per pencil while selling pencils of her old stock. In the next month she earns neither profit nor loss. If she sold $70$ pens, how many pencils did she sell?
AnswerGiven that,
In the next month there is neither profit nor loss
So, Profit earned $+$ Loss incurred $= 0$
i.e., Profit earned $= –$ Loss incurred.
Now, profit earned by selling $70$ pens $= ₹ 70$
Hence, loss incurred by selling pencils $= ₹ 70$
which we indicate by $– ₹ 70$ or $– 7,000$ paise
Therefore, Total number of pencils sold $= (–7000) ÷ (– 40) = 175$ pencils
View full question & answer→Question 391 Mark
A shopkeeper earns a profit of $₹ 1$ by selling one pen and incurs a loss of $40$ paise per pencil while selling pencils of her old stock. In a particular month she incurs a loss of $₹ 5$. In this period, she sold $45$ pens. How many pencils did she sell in this period?
AnswerGiven that,
Profit earned by selling one pen $= ₹ 1$
Profit earned by selling $45$ pens $= ₹ 45$, which we denote by $+ ₹ 45$
Total loss given $= ₹ 5$, which we denote by $– ₹ 5$
Profit earned $+$ Loss incurred = Total loss
Therefore, Loss incurred = Total Loss – Profit earned
$=₹ (– 5 – 45) = ₹ (–50) = –5000$ paise
Loss incurred by selling one pencil $= 40$ paise which we write as $– 40$ paise
Therefore, the number of pencils sold $= (–5000) \div (– 40) = 125.$
View full question & answer→Question 401 Mark
In a test $(+5)$ marks are given for every correct answer and $(–2)$ marks are given for every incorrect answer. Jay also answered all the questions and scored $(–12)$ marks though he got $4$ correct answers. How many incorrect answers had they attempted?
AnswerAccording to question,
Marks given for $4$ correct answers $= 5 \times 4 = 20$
Jay’s score $= –12$
Marks obtained for incorrect answers $= –12 – 20 = – 32$
Marks given for one incorrect answer $= (–2)$
Therefore, number of incorrect answers $= (–32) \div (–2) = 16$
View full question & answer→Question 411 Mark
In a test $(+5)$ marks are given for every correct answer and $(–2)$ marks are given for every incorrect answer. Radhika answered all the questions and scored $30$ marks though she got $10$ correct answers.
AnswerAccording to question,
Marks given for one correct answer $= 5$
So, marks given for $10$ correct answers$ = 5 \times 10 = 50$
Radhika’s score $= 30$
Marks obtained for incorrect answers $= 30 – 50 = – 20$
Marks given for one incorrect answer $= (–2)$
Therefore, number of incorrect answers$ = (–20) \div (–2) = 10$
View full question & answer→