2 Marks Questions

Question 12 Marks

Verify that a $\div$ $(b + c)$ $\neq$ $(a $$\div$ $b) + (a$ $\div$ $c)$ for the values of $a, b,$ and $c, a = (–10), b = 1, c = 1$

Answer

$a$ $\div$ $(b + c) = (–10)$ $\div$ $(1 + 1) = (–10)$ $\div$ $2 = –5$
$(a$ $\div$ $b) + (a$ $\div$ $c) = (–10)$ $\div$ $1 + (–10)$ $\div$ $1 = (–10) + (–10) = –20$
So, $a$ $\div$ $(b + c)$ $\neq$ $(a$ $\div$ $b) + (a$ $\div$ $c)$

View full question & answer→

Question 22 Marks

Verify that a $\div$ $(b + c)$ $\neq$ $(a$ $\div$ $b) + (a$ $\div$ $c)$ for the values of $a, b,$ and $c, a = 12, b = –4, c = 2$.

Answer

$a$ $\div$ $(b + c) = 12$ $\div$ $[(–4) + 2] = 12$ $\div$ $(–2) = –6$
$(a$ $\div$ $b) + (a$ $\div$ $c) = 12$ $\div$ $(–4) + (12$ $\div$ $2) = –3 + 6 = 3$
So, $a$ $\div$ $(b + c)$ $\neq$ $(a$ $\div$ $b) + (a$ $\div$ $c)$

View full question & answer→

Question 32 Marks

Starting from $(–1)$ $\times$ $5$, write various products showing some pattern to show $(–1)$ $\times$ $(–1) = 1.$

Answer

From the question, we obtain,
- $1$ $\times$ $5 = - 5$
- $1 $$\times$ $4 = - 4 = - 5 + 1$
- $1$ $\times$ $3 = - 3 = - 4 + 1$
- $1$ $\times$ $2 = - 2 = - 3 + 1$
- $1$ $\times$ $1 = - 1 = - 2 + 1$
- $1$ $\times$ $0 = 0 = - 1 + 1$
Therefore, - $1$ $\times$ $(-1) = 0 + 1 = 1$

View full question & answer→

Question 42 Marks

Verify: $(–21)$ $\times$ $[(–4) + (–6)] = [(–21)$ $\times$ $(–4)] + [(–21)$ $\times$ $(–6)]$

Answer

$L.H.S. = (–21) \times [(–4) + (–6)] = [(–21) \times (–10)]$
$= 21 \times 10 = 210$
$R.H.S. = [(–21) \times (–4)] + [(–21) \times (–6)]$
$= (21 \times 4) + (21 \times 6) = 84 + 126 = 210$
So, $(–21) \times [(–4) + (–6)] = [(–21) \times (–4)] + [(–21) \times (–6)]$

View full question & answer→

Question 52 Marks

Verify: $18$ $\times$$ [7 + (–3)] = [18$ $\times$ $7] + [18$ $\times$ $(–3)]$

Answer

$L.H.S. = 18 \times [7 + (–3)] = 18 \times [(7 – 3)]$
$= 18 \times (4) = 18 \times 4 = 72$
$R.H.S. = [18 \times 7] + [18 \times (–3)] = 126 + [–(18 \times 3)]$
$= 126 + (–54) = 126 – 54 = 72$
So, $18 \times [7 + (–3)] = [18 \times 7] + [18 \times (–3)]$

View full question & answer→

Question 62 Marks

In a quiz, team A scored $-40, 10, 0$ and team $B$ scored $10, 0, -40$ in three successive rounds. Which team scored more? Can we say that we can add integers in any order?

Answer

Total score of team
$A = -40 + 10 + 0 = -30$
Total score of team
$B = 10 + 0 + (-40) = 10 + 0 - 40 = - 30$
$\therefore$ The scores of both the teams are same i.e. $- 30$
Yes, we can add the integers in any order.

View full question & answer→

Question 72 Marks

Verify $(–30)$ $\times$ $[13 + (–3)] = [(–30)$ $\times$ $13] + [(–30)$ $\times$ $(–3)]$

Answer

Here,
$(–30)$ $\times$ $[13 + (–3)] = (–30)$ $\times$ $10 = –300$
and, $[(–30)$ $\times$ $13] + [(–30)$ $\times$ $(–3)] = –390 + 90 = –300$
Therefore, $(–30)$ $\times$ $[13 + (–3)] = [(–30)$ $\times$ $13] + [(–30)$ $\times$ $(–3)]$

View full question & answer→

Maths 2 Marks Questions

Take a timed test