Question 12 Marks
Find the amount to be paid at the end of $3$ years in each case:Principal $=₹ 7,500$ at $5 \%$ p.a.
AnswerHere, Principal $(P)=₹ 7,500$,
Rate $(\mathrm{R})=5 \%$ p.a.,
Time $(\mathrm{T})=3$ years
Simple Interest $=\frac{\mathrm{P} \times \mathrm{R} \times \mathrm{T}}{100}=\frac{7500 \times 5 \times 3}{100}=₹ 1,125$
Now, Amount = Principal + Simple Interest $=₹ 7,500+₹ 1,125=₹ 8,625$
View full question & answer→Question 22 Marks
Find the amount to be paid at the end of $3$ years in each case:Principal $=₹ 1,200$ at $12 \%$ $p.a.$
AnswerHere, Principal $(P)=₹ 1,200$,
Rate $(R)=12 \%$ $p.a.$,
Time $(T)=3$ years
Simple Interest $=\frac{\mathrm{P} \times \mathrm{R} \times \mathrm{T}}{100}=\frac{1200 \times 12 \times 3}{100}=₹ 432$
Now, Amount = Principal + Simple Interest $=₹ 1200+₹ 432=₹ 1,632$
View full question & answer→Question 32 Marks
Amina buys a book for $₹ 275$ and sells it at a loss of $15 \%$. How much does she sell it for?
AnswerThe cost of a book $=₹ 275$ and loss percent $= 15\%$
Loss = Loss $\%$ of $C.P.$ $=15 \%$ of $₹2$ $275=\frac{15}{100} \times 275=₹ 41.25$
Therefore, $S.P. = C.P.$ - Loss$= ₹275$ $-₹ 41.25=₹ 233.75$
Hence, Amina sells a book for $₹ 233.75$.
View full question & answer→Question 42 Marks
Juhi sells a washing machine for $₹ 13,500$. She loses $20 \%$ in the bargain. What was the price at which she bought it?
AnswerSelling price of washing machine $=₹ 13,500$
Loss percent $=20 \%$
Let the cost price of washing machine be $₹ x$.
Since, Loss = Loss $\%$ of $C.P.$
$\Rightarrow $ Loss $=20 \%$ of $₹ x=\frac{20}{100} \times x=\frac{x}{5}$
Therefore, $S.P.$ $=$ $C.P.$ - Loss
$\Rightarrow 13500=x-\frac{x}{5}$
$\Rightarrow x=\frac{13500 \times 5}{4}=₹ 16,875$
Hence, the cost price of washing machine is ₹16,875.
View full question & answer→Question 52 Marks
Ibuy a $T.V.$ for $₹ 10,000$ and sell it at a profit of $20 \%$. How much money do $I$ get for it?
AnswerThe cost price of $T.V.$ $=₹ 10,000$
Profit percent $=20 \%$
Now, Profit $=$ Profit $\%$ of $C.P.$ $=\frac{20}{100} \times 10000=₹ 2,000$
Selling price $=$ $C.P.$ + Profit $=₹ 10,000+₹ 2,000=₹ 12,000$
Hence, he gets $₹ 12,000$ on selling his $T.V.$
View full question & answer→Question 62 Marks
Arun bought a car for $₹ 3,50,000$. The next year, the price went upto $₹ 3,70,000$. What was the Percentage of price increase?
AnswerIncreased in price of a car from $₹ 3,50,000$ to $₹ 3,70,000$.
Amount change $=₹ 3,70,000-₹ 3,50,000=₹ 20,000$.
Therefore, increased percentage $=\frac{\text { Amount of change }}{\text { Original amount }} \times 100=\frac{20000}{350000} \times 100=5 \frac{5}{7} \%$
Hence, the percentage of price increased is $5 \frac{5}{7} \%$.
View full question & answer→Question 72 Marks
Convert each part of the ratio to percentage:$1: 2: 5$
Answer$1: 2: 5$Total part $=1+2+5=8$
Therefore, Fractional part $=\frac{1}{8}: \frac{2}{8}: \frac{5}{8}$
$\Rightarrow$ Percentage of parts $=\frac{1}{8} \times 100: \frac{2}{8} \times 100: \frac{5}{8} \times 100$
$\Rightarrow$ Percentage of parts $=12.5 \%: 25 \%: 62.5 \%$
View full question & answer→Question 82 Marks
Convert each part of the ratio to percentage:$1: 4$
Answer$1: 4$Total part $=1+4=5$
Therefore, Fractional part $=\frac{1}{5}: \frac{4}{5}$
$\Rightarrow$ Percentage of parts $=\frac{1}{5} \times 100: \frac{4}{5} \times 100$
$\Rightarrow$ Percentage of parts $=20 \%: 80 \%$
View full question & answer→Question 92 Marks
Convert each part of the ratio to percentage:$2: 3: 5$
Answer$2: 3: 5$Total part $=2+3+5=10$
Therefore, Fractional part $=\frac{2}{10}: \frac{3}{10}: \frac{5}{10}$
$\Rightarrow$ Percentage of parts $=\frac{2}{10} \times 100: \frac{3}{10} \times 100: \frac{5}{10} \times 100$
$\Rightarrow$ Percentage of parts $=20 \%: 30 \%: 50 \%$
View full question & answer→Question 102 Marks
Convert each part of the ratio to percentage:$3: 1$
Answer$3: 1$Total part $=3+1=4$
Therefore, Fractional part $=\frac{3}{4}: \frac{1}{4}$
$\Rightarrow \text { Percentage of parts }=\frac{3}{4} \times 100: \frac{1}{4} \times 100 $
$\Rightarrow \text { Percentage of parts }=75 \%: 25 \%$
View full question & answer→Question 112 Marks
Tell what is the profit or loss in the following transactions. Also find profit per cent or loss per cent in each case.A skirt bought for $₹ 250$ and sold at $₹ 150$ .
AnswerCost price of skirt = $₹ 250$Selling price of skirt $=₹ 150$
Since, $C.P. > S.P.$, therefore here is loss.
$\therefore$ Loss $=$ $C.P. - S.P.$ $=₹ 250-₹ 150=₹ 100$
Now Loss $\%=\frac{\text { Loss }}{\text { C.P. }} \times 100=\frac{100}{250} \times 100=40 \%$
Therefore, Profit $=₹ 100$ and Profit $\%=40 \%$
View full question & answer→Question 122 Marks
Tell what is the profit or loss in the following transactions. Also find profit per cent or loss per cent in each case.A cupboard bought for $₹ 2,500$ and sold at $₹ 3,000$.
AnswerCost price of cupboard $=₹ 2,500$
Selling price of cupboard $=₹ 3,000$
Since, $S.P. >C.P.$, therefore here is profit.
$\therefore$ Profit $=$ $S.P. - C.P.$ $=₹ 3,000-₹ 2,500=₹ 500$
Now Profit $\%=\frac{\text { Profit }}{\text { C.P. }} \times 100=\frac{500}{2500} \times 100=20 \%$
Therefore, Profit $=₹ 500$ and Profit $\%=20 \%$
View full question & answer→Question 132 Marks
Tell what is the profit or loss in the following transactions. Also find profit per cent or loss per cent in each case. A refrigerater bought for $₹ 12,000$ and sold at $₹ 13,500$.
AnswerCost price of refrigerator $=₹ 12,000$Selling price of refrigerator $=₹ 13,500$
Since, $S.P. >C.P.$, therefore here is profit.
$\therefore$ Profit $=$ $S.P. - C.P.$ $=₹ 13500-₹ 12000=₹ 1,500$
Now Profit $\%=\frac{\text { Profit }}{\text { C.P. }} \times 100=\frac{1500}{12000} \times 100=12.5 \%$
Therefore, Profit $=₹ 1,500$ and Profit $\%=12.5 \%$
View full question & answer→Question 142 Marks
If Meena gives an interest of $₹ 45$ for one year at $9 \%$ rate $p.a.$. What is the sum she has borrowed?
AnswerSimple Interest $=₹ 45$, Rate $(R)=9 \%$ p.a., Time $(T)=1$ years
$\text { Simple Interest }=\frac{P \times R \times T}{100} \Rightarrow 45=\frac{P \times 9 \times 1}{100}$
$\Rightarrow P=\frac{45 \times 100}{9 \times 1} \Rightarrow P=₹ 500$
Hence, she borrowed $₹ 500$ .
View full question & answer→Question 152 Marks
Tell what is the profit or loss in the following transactions. Also find profit per cent or loss per cent in each case.Gardening shears bought for $₹ 250$ and sold for $₹ 325$.
AnswerCost price of gardening shears $=₹ 250$
Selling price of gardening shears $=₹ 325$
Since, $S.P.$ $>$ $C.P.$, therefore here is profit.
$\therefore \text { Profit }=\text { S.P. }- \text { C.P. }=₹ 325-₹ 250=₹ 75$
Now Profit $\%=\frac{\text { Profit }}{\text { C.P. }} \times 100=\frac{75}{250} \times 100=30 \%$
Therefore, Profit $= ₹75$ and Profit $\%=30 \%$
View full question & answer→Question 162 Marks
What rate gives $₹ 280$ as interest on a sum of $₹ 56,000$ in $2$ years?
AnswerHere, Principal $(P)=₹ 56,000$,
Simple Interest $(S.I.)$ = $₹ 280$,
Time $(T)=2$ years
Simple Interest $=\frac{\mathrm{P} \times \mathrm{R} \times \mathrm{T}}{100} \Rightarrow 280=\frac{56000 \times \mathrm{R} \times 2}{100}$
$\Rightarrow \mathrm{R}=\frac{280 \times 100}{56000 \times 2} \Rightarrow \mathrm{R}=0.25 \%$
Hence, the rate of interest on sum is $0.25 \%$.
View full question & answer→Question 172 Marks
Meeta saves $₹ 4000$ from her salary. If this is $10 \%$ of her salary. What is her salary?
AnswerLet Meera's salary be $₹ x$.
Now, $10 \%$ of salary $=₹ 400$
$\Rightarrow 10 \% \text { of } x=₹ 400 $
$\Rightarrow \frac{10}{100} \times x=400 $
$\Rightarrow x=\frac{400 \times 100}{10} $
$\Rightarrow x=4,000$
Hence, Meera's salary is $₹ 4,000..$
View full question & answer→Question 182 Marks
Out of $15,000$ voters in a constituency, $60 \%$ voted. Find the percentage of voters who did not vote. Can you now find how many actually did not vote?
AnswerTotal voters $=15,000$
Percentage of voted candidates $=60 \%$
Percentage of not voted candidates $=100-60=40 \%$
Actual candidates, who did not vote $=40 \%$ of $15000=\frac{40}{100} \times 15000=6,000$
Hence, $6,000$ candidates did not vote.
View full question & answer→Question 192 Marks
In a city, $30 \%$ are females, $40 \%$ are males and remaining are children. What per cent are children?
AnswerGiven: Percentage of females $=30 \%$
Percentage of males $=40 \%$
Total percentage of females and males $=30+40=70 \%$
Percentage of children
$=$ Total percentage - Percentage of males and females
$=100 \%-70 \%=30 \%$
Hence, $30 \%$ are children.
View full question & answer→Question 202 Marks
A local cricket team played $20$ matches in one season. It won $25 \%$ of them. How many matches did they win?
AnswerNumber of matches played by cricket team $=20$
Percentage of won matches $=25 \%$
Total matches won by them $=25 \%$ of $20=\frac{25}{100} \times 20=5$
Hence, they won $5$ matches.
View full question & answer→Question 212 Marks
An article was purchased for $₹1239$ including $GST$ of $18\%$. Find the price of the article before $GST$ was added?
View full question & answer→Question 222 Marks
The price of a $TV$ is ₹ $13,000$. The sales tax charged on it is at the rate of $12\%$. Find the amount that Vinod will have to pay if he buys it.
AnswerMarked price of the $TV = ₹ 13,000$
$S T =12 \% $
$S P =M P \times\left(1+\frac{S T}{100}\right)$
$ =13,000 \times\left(1+\frac{12}{100}\right)$
$ =13,000 \times \frac{112}{100}=₹ 14,560$
The required amount that Vinod has to pay $= ₹ 14,560$
View full question & answer→Question 232 Marks
A football team won $10$ matches out of the total number of matches they played. If their win percentage was $40$, then how many matches did they play in all?
Answer$40$ matches the team won out of $100$ matches
$1$ match was won out of $\frac{100}{40}$ matches $10$ matches the team will won out of $\frac{100}{40} \times 10=25$ matches Hence, the total number of matches played by the team $=25$
View full question & answer→Question 242 Marks
An article was purchased for $₹ 1239$ including $GST$ of $18\%.$ Find the price of the article before $GST $was added?
View full question & answer→Question 252 Marks
I purchased a hair-dryer for $₹ 5,400$ including $8\% VAT.$ Find the price before $VAT$ was added.
View full question & answer→Question 262 Marks
Arun bought a pair of skates at a sale where the discount given was $20\%$. If the amount he pays is ₹ $1,600$, find the marked price.
View full question & answer→Question 272 Marks
The price of a $TV$ is ₹ $13,000$. The sales tax charged on it is at the rate of $12\%$. Find the amount that Vinod will have to pay if he buys it.
View full question & answer→Question 282 Marks
During a sale, a shop offered a discount of $10\%$ on the marked prices of all the items. What would a customer have to pay for a pair of jeans marked at ₹ $1450$ and two shirts marked at ₹ $850$ each?
View full question & answer→Question 292 Marks
Find CI on ₹ 12600 for 2 years at $10 \%$ per annum compounded annually.
AnswerWe have, $A = P \left(1+\frac{ R }{100}\right)^n$, where Principal (P) = ₹ 12600, Rate (R) = 10, Number of years (n) = 2
= ₹ $12600\left(1+\frac{10}{100}\right)^2$ = ₹ $12600\left(\frac{11}{10}\right)^2$
= ₹ $12600 \times \frac{11}{10} \times \frac{11}{10}$ = ₹ 15246
CI = A - P ₹ 15246 - ₹ 12600 + ₹ 2646
View full question & answer→Question 302 Marks
A sum of ₹ 10,000 is borrowed at a rate of interest $15 \%$ per annum for 2 years. Find the simple interest on this sum and the amount to be paid at the end of 2 years.
AnswerOn ₹100, interest charged for 1 year is₹ 15.
So, on ₹ 10,000, interest charged $=\frac{15}{100} \times 10000$ = ₹ 15000
Interest for 2 years = ₹1500 × 2 = ₹ 3000
Amount to be paid at the end of 2 years = Principal + Interest
= ₹ 10000+ ₹ 3000 = ₹ 13000
View full question & answer→Question 312 Marks
Salim bought an article for ₹ 784 which included GST of $12 \%$. What is the price of the article before GST was added?
AnswerLet original price of the article be ₹ 100. GST = 12%.
Price after GST is included = ₹ (100 + 12) = ₹ 112
When the selling price is ₹ 112 then original price = ₹ 100.
When the selling price is ₹ 784, then original price = ₹ $\frac{100}{12} \times 784=$ ₹ 700
View full question & answer→Question 322 Marks
(Value Added Tax (VAT)) Waheeda bought an air cooler for ₹ 3300 including a tax of $10 \%$. Find the price of the air cooler before VAT was added.
AnswerThe price includes the VAT, i.e., the value added tax. Thus, a 10% VAT means if the price without VAT is₹ 100 then price including VAT is ₹ 110.
Now, when price including VAT is 110, original price is ₹100.
Hence when price including tax is₹ 3300, the original price = ₹ $\frac{100}{110} \times 3300$ = ₹ 3000
View full question & answer→Question 332 Marks
(Finding Sales Tax) The cost of a pair of roller skates at a shop was ₹ 450 . The sales tax charged was $5 \%$. Find the bill amount.
AnswerOn ₹100, the tax paid was ₹ 5.
On₹450, the tax paid would be = ₹ $\frac{5}{100} \times 450$
= ₹ 22.50
Bill amount = Cost of item + Sales tax = ₹ 450 + ₹ 22.50 = ₹ 472.50.
View full question & answer→Question 342 Marks
An item marked at ₹ 840 is sold for ₹ 714 . What is the discount and discount $\%$ ?
AnswerDiscount = Marked Price - Sale Price
= ₹ 840 - 714
= ₹ 126
On marked price of 840, the discount is ₹126.
On MP of ₹ 100, how much will the discount be?
Discount $=\frac{126}{840} \times 100 \%=15 \%$
View full question & answer→