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Maths 1 Marks Question

Factorisation · Jharkhand Board (JAC) STD 8 (Jharkhand - English Medium). 20 questions.

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1 Marks Question

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20 questions · 1 auto-graded MCQ + 19 self-marked written.

Question 11 Mark
Factorise:
$x^3(2a - b) + x^2(2a - b)$
Answer
$x^3(2a - b) + x^2(2a - b)$
$x^3(2a - b) + x^2(2a - b)$
$= (2a - b)(x + 1)$
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Question 41 Mark
Factorise:
$ -5 - 10t + 20t^2$
Answer
$-5 - 10t + 20t^2$
$= -5(1 + 2t - 4t^2) (HCF\  of\  5, 10, 20 = 5)$
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Question 61 Mark
Factorise:
$9x^3 - 6x^2 + 12x$
Answer
$9x^3 - 6x^2 + 12x$
$= 3x(3x^2 - 2x + 4) (HCF \ of \  9, 6, 12 = 3)$
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Question 71 Mark
Factorise:
$36x^3y - 60x^2y^2z$
Answer
$36x^3y - 60x^2y^2z$= $12x^2y(3x - 5y^2z) (HCF$  of $36$ and  $60 = 12)$
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Question 91 Mark
Factorise:
$14x^3 + 21x^4y - 28x^2y^2$
Answer
$14x^3 + 21x^4y - 28x^2y^2$
 $= 14x^2(2x + 3x^2y - 4y^2)(HCF $ of $ 14, 21, 28 = 7)$
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Question 121 Mark
Factorise:
$12 x^2 y^3-21 x^3 y^2$
Answer
$12 x^2 y^3-21 x^3 y^2=3 x^2 y^2(4 y-7 x)(HCF$ of $12$ and $21=3)$
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Question 141 Mark
Factorise:
$18 a^3 b^3-27 a^2 b^3+36 a^3 b^2$
Answer
$18 a^3 b^3-27 a^2 b^3+36 a^3 b^2$
= $18 a^2 b^2(2 a b-3 b+4 a)($ HCF of $10,27,36=9)$
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MCQ 191 Mark
Tick $(\checkmark)$ the correct answer:
 $6a^2 - 13a + 6 = ?$
  • A
    $(2 a+3)(3 a-2)$
  • B
    $(2 a-3)(3 a+2)$
  • ✓
    $(3 a-2)(2 a-3)$
  • D
    $(3 a+1)(2 a-3)$
Answer
Correct option: C.
$(3 a-2)(2 a-3)$
$ 6 a^2-13 a+6 $
$ \{36=6 \times 6,36=(-9) \times(-4),-13=-9-4\} $
$ =3 a(2 a-3)-2(2 a-3) $
$ =(3 a-2)(2 a-3)$
 
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