Download App

Quadrilaterals Maths - Quadrilaterals

Jharkhand Board (JAC) - STD 9 - Maths (Jharkhand - English Medium). 103 questions in this chapter.

Question types

Quadrilaterals question types

103 questions across 5 question groups — pick any mix to generate a Maths paper with step-by-step answer keys.

103
Questions
5
Question groups
5
Question types
Sample Questions

Quadrilaterals questions

One sample from each question group in this chapter. Select any group above to see the full set with answer keys.

Q 1M.C.Q1 Mark
Three statements are given below:
$i.$ In a rectangle $\text{ABCD},$ the diagonal $AC$ bisects $\angle\text{A}$ as well as $\angle\text{C}.$
$ii.$ In a square $\text{ABCD}$, the diagonal $AC$ bisects $\angle\text{A}$ as well as $\angle\text{C}.$
$iii.$ In a rhombus $\text{ABCD},$ the diagonal $AC$ bisects $\angle\text{A}$ as well as $\angle\text{C}.$
Which is true$?$
  • A
    $I$ only
     
  • ✓
    $II$ and $III$
     
  • C
    $I$ and $III$
     
  • D
    $I$ and $II$

Answer: B.

View full solution →
Q 2M.C.Q1 Mark
The figure formed by joining the mid-points of the adjacent sides of a rhombus is a:
  • A
    Rhombus.
  • B
    Square.
  • ✓
    Rectangle.
  • D
    Parallelogram.

Answer: C.

View full solution →
Q 3M.C.Q1 Mark
In the given figure, $ABCD$ is a parallelogram in which $\angle\text{BDC}=45^{\circ}$ and $\angle\text{BAD}=75^{\circ}.$ Then, $\angle\text{CBD}=?$
  • A
    $45^\circ$
  • B
    $55^\circ$
  • ✓
    $60^\circ$
  • D
    $75^\circ$

Answer: C.

View full solution →
Q 4M.C.Q1 Mark
Three statements are given below:
$i.$ In a $\| gm$, the angle bisectors of two adjacent angles enclose a right angle.
$ii.$ The angle bisectors of a $\| gm$ form a rectangle.
$iii.$ The triangle formed by joining the mid$-$points of the sides of an isosceles triangle is not necessarily an isosceles triangle.
Which is true?
  • A
    $I$ only
     
  • B
    $II$ only
     
  • ✓
    $I$ and $II$
     
  • D
    $II$ and $III$

Answer: C.

View full solution →
Q 5M.C.Q1 Mark
If area of a $||\ gm$ with sides a and $b$ is $A$ and that of a rectangle with sides a and $b$ is $B,$ then:
  • A
    $A > B$
  • B
    $A = B$
  • ✓
    $A < B$
  • D
    $A ≥ B$

Answer: C.

View full solution →
Q 82 Marks Questions2 Marks
In the adjoining figure, $ABCD$ is a trapezium in which $AB \| DC$. If $\angle\text{A}=55^{\circ}$ and $\angle\text{B}=70^{\circ},$ find $\angle\text{C}$ and $\angle\text{D}.$
View full solution →
Q 92 Marks Questions2 Marks
In a parallelogram $ABCD$, points $M$ and $N$ have been taken on opposite sides $AB$ and $CD$ respectively such that $AM = CN.$ Show that $AC$ and $MN$ bisect each other.
View full solution →
Q 113 Marks Question3 Marks
$M$ and $N$ are points on opposite sides $AD$ and $BC$ of a parallelogram $ABCD$ such that $MN$ passes through the point of intersection $O$ of its diagonals $AC$ and $BD.$ Show that $MN$ is bisected at $O.$
View full solution →
Q 123 Marks Question3 Marks
In the adjoining figure, $M$ is the midpoint of side $BC$ of a parallelogram $ABCD$ such that $\angle\text{BAM}=\angle\text{DAM}.$ Prove that $AD = 2CD.$
View full solution →
Q 145 Marks Questions5 Marks
In the adjoining figure, $ABCD$ is a parallelogram in which $\angle\text{DAB}=80^{\circ}$ and $\angle\text{DBC}=60^{\circ}.$ Calculate $\angle\text{CDB}$ and $\angle\text{ADB}.$
View full solution →
Q 165 Marks Questions5 Marks
In the adjoining figure, $ABCD$ is a square. $A$ line segment $CX$ cuts $AB$ at $X$ and the diagonal $BD$ at $O$ such that $\angle\text{COD}=80^{\circ}$ and $\angle\text{OXA}=\text{x}^{\circ}.$ Find the value of x.
View full solution →
Q 194 Marks Questions4 Marks
In the adjoining figure,$ABCD$ is a parallelogram and $E$ is the midpoint of side $BC$. If $DE$ and $AB$ when produced meet at $F$, prove that $AF = 2AB$.
View full solution →
Q 214 Marks Questions4 Marks
In the adjoining figure, $ABCD$ is a parallelogram whose diagonals intersect each other at $O$. A line segment $EOF$ is drawn to meet $AB$ at $E$ and $DC$ at $F$. Prove that $OE = OF.$
View full solution →
Q 234 Marks Questions4 Marks
$P , Q, R$ and $S$ are respectively the midpoints of the sides $AB, BC, CD$ and $DA$ of a quadrilateral $\text{ABCD}$. Show that:
$i. PQ \| AC$ and $\text{PQ}=\frac{1}{2}\text{AC}$
$ii. PQ \| SR$
$iii. \text{PQRS}$ is a parallelogram.
View full solution →
Browse all question groups ↑

Generate a Quadrilaterals paper free

Pick question groups from the list above, set marks and difficulty, and export a branded PDF with step-by-step answer keys. First 3 chapters free — no signup.

Download App
Generate Paper FreeAll Maths chapters