MCQ 511 Mark
In the figure, the perimeter of $\triangle\text{ABC}$ is:
- ✓$30\ cm$
- B$60\ cm$
- C$45\ cm$
- D$15\ cm$
Answer
By the property of tangent
$\text{AO = AR} = 4\ cm ($tangent from $A)$
$\text{BR = BP} = 6\ cm ($tangent from $B)$
$\text{PC = CQ} = 5\ cm ($tangent from $C)$
Perimeter of $\triangle\text{ABC = AB + BC + CA}$
Perimeter of $\triangle\text{ABC = AR + BR + BP + PC + CQ + QA}$
Perimeter of $\triangle\text{ABC} = 4 + 6 + 6 + 5 + 5 + 4$
Perimeter of $\triangle\text{ABC} = 30\ cm$
View full question & answer→Correct option: A.
$30\ cm$
By the property of tangent
$\text{AO = AR} = 4\ cm ($tangent from $A)$
$\text{BR = BP} = 6\ cm ($tangent from $B)$
$\text{PC = CQ} = 5\ cm ($tangent from $C)$
Perimeter of $\triangle\text{ABC = AB + BC + CA}$
Perimeter of $\triangle\text{ABC = AR + BR + BP + PC + CQ + QA}$
Perimeter of $\triangle\text{ABC} = 4 + 6 + 6 + 5 + 5 + 4$
Perimeter of $\triangle\text{ABC} = 30\ cm$