M.C.Q (1 Marks)

MCQ 11 Mark

The formula to find mean by step deviation method is

A
$\frac{\sum f_i u_i}{\sum f_i}$
B
$A+\bar{d}$
C
$A +g \bar{u}$
D
None of these

Answer

$A +g \bar{u}$

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MCQ 21 Mark

The formula of mode is

✓
$L+\left[\frac{f_1-f_0}{2 f_1-f_0-f_2}\right] \times h$
B
$L-\left[\frac{f_1-f_0}{2 f_1-f_0-f_2}\right] \times h$
C
$L+\left[\frac{f_1-f_0}{2 f_1-f_0+f_2}\right] \times h$
D
$L-\left[\frac{f_1-f_0}{2 f_1-f_0-f_2}\right] \times \frac{1}{h}$

Answer

Correct option: A.

$L+\left[\frac{f_1-f_0}{2 f_1-f_0-f_2}\right] \times h$

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MCQ 31 Mark

If $\Sigma f_id_i=1885$ and $\Sigma f_i=100$, then the value of $\bar{d}$ is

A
1.885
✓
18.85
C
188.5
D
1885

Answer

Correct option: B.

18.85

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MCQ 41 Mark

The value of lower limit ( L ) in the above example to calculate median is

A
$0$
B
10
✓
20
D
30

Answer

Correct option: C.

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MCQ 51 Mark

The median class for the following frequency distribution is

Class interval	0-10	10-20	20-30	30-40
Frequency	5	7	13	18

A
$0-10$
B
$10-20$
✓
$20-30$
D
$30-40$

Answer

Correct option: C.

$20-30$

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MCQ 61 Mark

In step deviation method, $u$ is given by

A
$A+\bar{d}$
B
$x_i- A$
C
$\frac{x_i+A}{g}$
✓
$\frac{x_i-A}{g}$

Answer

Correct option: D.

$\frac{x_i-A}{g}$

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MCQ 71 Mark

The formula to find the mean deviation ( $\bar{d}$ ) in Assumed mean method is

A
$\bar{d} \frac{\sum f_i d_i}{\sum d_i}$
B
$\sum f_i d_i$
✓
$\frac{\sum f_i d_i}{\sum f_i}$
D
None of the above.

Answer

Correct option: C.

$\frac{\sum f_i d_i}{\sum f_i}$

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MCQ 81 Mark

The formula for median is

A
$\frac{L}{2}+\left(\frac{N}{2}-\right.$ c.f. $) \frac{h}{f}$
B
$L+\left(\frac{N}{2}-c_{.} f_{.}\right) \frac{h}{f}$
C
$L+\left(\frac{N}{2}-c_{.} f_{.}\right) \frac{f}{h}$
D
$L+\left(\frac{N}{2}-f\right) \frac{c \cdot f}{h}$

Answer

$L+\left(\frac{N}{2}-c . f.\right) \frac{h}{f}$

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MCQ 91 Mark

Class width of any class interval is ....

A
Lower limit + upper limit
B
Lower limit-upper limit
✓
Upper limit - lower limit
D
None of the above.

Answer

Correct option: C.

Upper limit - lower limit

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MCQ 101 Mark

The formula to find mean by direct method is

A
$A+\bar{d}$
B
$\frac{\sum f_i d_i}{\sum f_i}$
C
$\frac{\sum f_i d_i}{\sum d_i}$
D
$\frac{\sum f_j x_i}{\sum f_i}$

Answer

$\frac{\sum f_i x_i}{\sum f_i}$

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MCQ 111 Mark

No of trees planed by each student	1 - 3	4 - 6	7 - 9	10 - 12
No of students	7	8	6	4

The above data is to be shown by a frequency polygon. The coordinates of the points to show number of students in the class 4 – 6 are.

A
(4, 8)
B
(3,5)
✓
(5,8)
D
(8,4)

Answer

Correct option: C.

(5,8)

(C)(5, 8)
Class mark = 5
Frequency = 8
∴ Co-ordinates of the point = (5, 8)

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MCQ 121 Mark

Distance Converd per line(km)	12 - 14	14 - 16	16 - 18	18 -20
No of cars	11	12	20	7

The median of the distances covered per litre shown in the above data is in the group

A
12 – 14
B
14 – 16
✓
16 – 18
D
18 – 20

Answer

Correct option: C.

16 – 18

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MCQ 131 Mark

The formula to find mean from a grouped frequency table is $\overline{\overline{ X }}= A +\frac{\sum f_i u_i}{\sum f_i} \times g$ in the formula $u _{ i }$ = _________.

A
$\frac{x_i+ A }{g}$
B
$\left(x_i- A \right)$
✓
$\frac{x_i- A }{g}$
D
$\frac{ A -x_i}{g}$

Answer

Correct option: C.

$\frac{x_i- A }{g}$

(C)$\frac{x_i- A }{g}$
$u_i=\frac{d_i}{g}=\frac{x_{ i }- A }{g}$

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MCQ 141 Mark

Cumulative frequencies in a grouped frequency table are useful to find.

A
Mean
✓
Median
C
Mode
D
All of these

Answer

Correct option: B.

Median

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MCQ 151 Mark

Different expenditures incurred on the construction of a building were shown by a pie diagram. The expenditure of ₹ 45,000 on cement was shown by a sector of central angle of 75°. What was the total expenditure of the construction?

✓
216000
B
360000
C
450000
D
750000

Answer

Correct option: A.

216000

(A) Measure of the central angle = $\frac{\text { Expenditure of cement }}{\text { Total expenditure }} \times 360^{\circ}$
$\therefore \quad$ Total expenditure $=\frac{45000 \times 360^{\circ}}{75^{\circ}}=₹ 2,16,000$

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MCQ 161 Mark

The persons of O – blood group are 40%. The classification of persons based on blood groups is to be shown by a pie diagram. What should be the measures of angle for the persons of O – blood group?