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Question 13 Marks
Answer
(a) Angles: O = $45\% \times 3.6 = 162^\circ$, A = $20\% \times 3.6 = 72^\circ$, B = $30\% \times 3.6 = 108^\circ$, AB = $5\% \times 3.6 = 18^\circ$.
(b) If 30% = 600, Total = $\frac{600}{30} \times 100 = 2000$ persons.
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Question 23 Marks
In a general store the prices of different articles and its demand is shown in the following frequency distribution table. Find the Median of the prices.
Price in RupeesNo. of Articles
Less than 20140
20 - 40100
40 - 6080
60 - 8060
80 - 10020
Answer
Total N = 400. N/2 = 200. Median class is 20-40 (since cf reaches 240).
L=20, f=100, cf=140, h=20.
Median = $L + [\frac{N/2 - cf}{f}]h = 20 + [\frac{200-140}{100}]20 = 20 + 12 = 32$
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