Question 11 Mark
If $f(2)=4, f^{\prime}(2)=1$, then find $\lim _{x \rightarrow 2}\left[\frac{x f(2)-2 f(x)}{x-2}\right]$
Answer
View full question & answer→$ \lim _{x \rightarrow 2} \frac{x f(2)-2 f(x)}{x-2}$
$=\lim _{x \rightarrow 2} \frac{f(2)-2 f^{\prime}(x)}{1} \quad \ldots[\text { By L'Hospital Rule] }$
$=f(2)-2 f^{\prime}(2)$
$=4-2(1)=2 $
[By L' Hospital Rule]
$=\lim _{x \rightarrow 2} \frac{f(2)-2 f^{\prime}(x)}{1} \quad \ldots[\text { By L'Hospital Rule] }$
$=f(2)-2 f^{\prime}(2)$
$=4-2(1)=2 $
[By L' Hospital Rule]